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Dafna1 [17]
4 years ago
9

Find the square root of 8-2√5​

Mathematics
2 answers:
Paraphin [41]4 years ago
6 0

Answer:

The square root of 8 - 2√5 is

\sqrt{4 +  \sqrt{11} }    \:  -  \sqrt{4  -   \sqrt{11} }

Step-by-step explanation:

To find the square root

8-2√5 must be in the form √a - √b where a > b

√ 8 - 2√5 = √a - √b

Square both sides

8 - 2√5 = (√a - √b)²

That's

8 - 2√5 = (a + b) - 2√ab

Since the two surd expressions are equal we can equate them

That's

8 = a + b ........ 1

a = 8 - b ........ 2

2√5 = 2√ab

Simplify

Divide both sides by 2

√5 = √ab

square both sides

We have

5 = ab ....... 3

Substitute a = 8 - b into equation 3

5 = ( 8 - b)b

5 = 8b - b²

b² - 8b + 5 = 0

After solving

b = 4 + √ 11 or 4 - √ 1

Since b is less than a

b = 4 - √11

a = 4 + √11

So the square root of 8 - 2√5 is

\sqrt{4 +  \sqrt{11} }    \:  -  \sqrt{4  -   \sqrt{11} }

Hope this helps you.

Alex787 [66]4 years ago
4 0

Answer:

1.88

Step-by-step explanation:

8-2√5=3.527864045

square root of 3.527864045=1.87826090972

the question will probably want it to 2d.p (decimal places) which means the answer would be 1.88

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