Find the difference x/7x^2-13x-24 - 2x/7x^2-30x+27
1 answer:
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Answer:
Step-by-step explanation:
GIVEN: A farmer has of fencing to construct a rectangular pen up against the straight side of a barn, using the barn for one side of the pen. The length of the barn is
.
TO FIND: Determine the dimensions of the rectangle of maximum area that can be enclosed under these conditions.
SOLUTION:
Let the length of rectangle be and
perimeter of rectangular pen
area of rectangular pen
putting value of
to maximize
but the dimensions must be lesser or equal to than that of barn.
therefore maximum length rectangular pen
width of rectangular pen
Maximum area of rectangular pen
Hence maximum area of rectangular pen is and dimensions are
To find conjecture about regular polygon, use the formula 
Where, n = number of sides of the regular polygone
1) Triangle
n =3
So, Conjecture of the triangle =
= 120
2) Square
n =4
So, Conjecture of the square =
= 90
3) Pentagone
n = 5
So, Conjecture of the pentagon =
= 72
4) Hexagone
n = 6
So, Conjecture of the pentagon =
= 60.
Where, n = number of sides of the regular polygone
1) Triangle
n =3
So, Conjecture of the triangle =
2) Square
n =4
So, Conjecture of the square =
3) Pentagone
n = 5
So, Conjecture of the pentagon =
4) Hexagone
n = 6
So, Conjecture of the pentagon =