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Irina18 [472]
3 years ago
15

What is the inverse operation of a number squared?

Mathematics
2 answers:
Sedbober [7]3 years ago
7 0
<span>Finding the square root.</span>
Lynna [10]3 years ago
3 0
Finding the square root
You might be interested in
Feliz is looking at a cyclic quadrilateral EFGH. He says, "I'm not convinced that opposite
azamat

If the angle G is moved to a different spot in the circle the angle FGH and angle FEH in the cyclic quadrilateral will change to make it supplementary.

<h3>How to find angles of cyclic quadrilateral?</h3>

A cyclic quadrilateral is inscribed in a circle. It has all its vertices on the circumference of the circle.

Opposite angles in a cyclic quadrilateral are supplementary angles. That means they add up to 180 degrees.

Therefore,

∠F + ∠H = 180°

∠G + ∠E = 180°

Hence, if we moved ∠G to a different spot on the circle, angle FGH would change but angle FEH will also change to make the two opposite angles supplementary.

Therefore, Felix was wrong.

learn more on cyclic quadrilateral here: brainly.com/question/21208662

#SPJ1

5 0
2 years ago
A rectangle has width that is 6 meters less than the length. The area of the rectangle is 280 square meters. Find the dimensions
salantis [7]

Dimensions are length 20 meter and width 14 meter

<em><u>Solution:</u></em>

Let "a" be the length of rectangle

Let "b" be the width of rectangle

Given that,

<em><u>A rectangle has width that is 6 meters less than the length</u></em>

Width = length - 6

b = a - 6

The area of the rectangle is 280 square meters

<em><u>The area of the rectangle is given by formula:</u></em>

Area = length \times width

<em><u>Substituting the values we get,</u></em>

Area = a \times (a-6)\\\\280 = a^2-6a\\\\a^2-6a -280=0

<em><u>Solve the above equation by quadratic formula</u></em>

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=1,\:b=-6,\:c=-280:\quad a_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:1\left(-280\right)}}{2\cdot \:1}

a =\frac{6 \pm \sqrt{36+1120}}{2}\\\\a = \frac{6 \pm \sqrt{1156}}{2}\\\\a = \frac{6 \pm 34}{2}\\\\Thus\ we\ have\ two\ solutions\\\\a = \frac{6+34}{2} \text{ or } a = \frac{6-34}{2}\\\\a = 20 \text{ or } a = -14

Since, length cannot be negative, ignore a = -14

<em><u>Thus solution of length is a = 20</u></em>

Therefore,

width = length - 6

width = 20 - 6 = 14

Thus dimensions are length 20 meter and width 14 meter

6 0
3 years ago
Convert to the given unit Quarts and cups
Gennadij [26K]

Answer: 20

Step-by-step explanation:

8 0
2 years ago
Please Help me solve this (Who ever answers correctly will get brainlest)
riadik2000 [5.3K]

Answer: im quite sure it's 4.12

Step-by-step explanation:

im so sure because i got it right <3

5 0
2 years ago
Read 2 more answers
HELP REAL QUICK PLS TY
Veronika [31]

Answer:

Step-by-step explanation:

the area is L x W so its 42cm

7 0
3 years ago
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