11
(9, 18, 27, 36, 45, 54, 63, 72, 81, 90 and 99)
Those numbers divisible by 9 are the multiple of 9; thus need to know how many multiples of 9 there are between 1 and 100:
100 ÷ 9 = 11 r 1 ÷ last multiple of 9 is 11 × 9 (= 99)
→ There are 11 - 1 + 1 = 11 numbers between 1 and 100 which are divisible by 9.
(They are 9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99.)
21 or two-one also known as the number after 22 and the number before 23. Hope this helped. ;)
Those are called "even numbers".
Also, I guess, "multiples of 2" .
130x5=650
650-104=546
546-137=409
409-154=255
255-131=124
x=124
