Answer:
Answer:
A) Total frequency = 30
B) Yes, the distribution is consistent with the label because the frequencies are greatest when the lengths are closest to the labeled size of 1/2 inches which is 0.5 inches.
Step-by-step explanation:
Since the class limit width is 0.010 from the question, we arrive at;
Class Limits Frequency
Length(Inches)
0.470 - 0.479 3
0.480 - 0. 489 5
0.490 - 0.499 9
0.500 - 0.509 12
0.510 - 0.519 1
D is the answer I believe
The metallurgist must use 5.538 pounds of an alloy with 39 % copper and 42.462 pounds of an alloy with 62 % copper.
<h3>How to calculate proportions of components associated to an alloy</h3>
Herein we must create a new alloy by using correct quantities of two alloys with distinct <em>copper</em> concentrations. All required information can be found by concept of <em>weighted</em> averages:
(62/100) · (48 lb) = (39/100) · x + (65/100) · (48 - x)
62 · 48 = 39 · x + 65 · 48 - 65 · x
3 · 48 = 26 · x
x = 5.538 lb
The metallurgist must use 5.538 pounds of an alloy with 39 % copper and 42.462 pounds of an alloy with 62 % copper.
To learn more on weighted averages: brainly.com/question/28053890
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Answer:
(-9, 9)
Step-by-step explanation:
(Given)
-1 -1 (Getting "x" alone)
(Cont. Getting "x" alone)
÷6 ÷6 ↓
↓
(9 and -9 squared are both equal to 81)
↓ ↓ ↓
x = 9 x = -9 (Answer)
Hope this Helps! :)
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