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garri49 [273]
3 years ago
8

I need the answer please. Because I think i got mine wrong

Mathematics
2 answers:
Bumek [7]3 years ago
8 0

Answer:

a.  1 / 8^2    b. 3^3    c 1 / 6^4.

Step-by-step explanation:

We used the following rules   x^-n = 1/x^n,  

1 / x^-n = x^n

and  x^n * x^m = x^(n+m).

Gekata [30.6K]3 years ago
7 0

Answer:

see explanation

Step-by-step explanation:

Using the rules of exponents

• a^{-m} ⇔ \frac{1}{a^{m} }

• a^{0} = 1

• a^{m} × a^{n} ⇔ a^{(m+n)}

Given

(a)

8^{-2} = \frac{1}{8^{2} }

(b)

\frac{1}{3^{-3} } = 3³

(c)

6^{-12} × 6^{8} × 6^{0}

= 6^{(-12+8)} × 1

= 6^{-4}

= \frac{1}{6^{4} }

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vovikov84 [41]
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8 0
3 years ago
Solve. 3(x-6)-2(2x+3)=14
coldgirl [10]

Answer:

x=-38

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3(x−6)−2(2x+3)=14

(3)(x)+(3)(−6)+(−2)(2x)+(−2)(3)=14(Distribute)

3x+−18+−4x+−6=14

(3x+−4x)+(−18+−6)=14(Combine Like Terms)

−x+−24=14

−x−24=14

Step 2: Add 24 to both sides.

−x−24+24=14+24

−x=38

Step 3: Divide both sides by -1.

−x

−1

=

38

−1

x=−38

5 0
3 years ago
Read 2 more answers
Find the y-intercept of the line on the graph.
BARSIC [14]
It's a little hard to see, but I'm almost positive the y intercept is -1.
 
Remember, the y intercept is wherever the line intercepts in the y axis 0.

Good luck my man.
5 0
3 years ago
Read 2 more answers
Put together, Dulcina and Tremaine have 129 total matchbooks. Tremaine's collection has 39 fewer matchbooks in it than Dulcina's
Anit [1.1K]

Answer:

Let the Dulcina's collection be 'x'

Let the Tremaine collection be 'x-39'

x + x - 39 =129

2x = 129 +39

2x = 168

x = 168/2

x = 84

Dulcina's collection = x = 84

Tremaine's collection = x - 39 = 84 - 39 = 45

7 0
3 years ago
A circus acrobat is shot out of a cannon. The equation for the acrobat's pathway can be modeled by h= -16t^2+25. How long will i
Alex_Xolod [135]
For this we almost have the following equation:
 h = -16t ^ 2 + 25&#10;
 We must match the equation to zero:
 -16t ^ 2 + 25 = 0&#10;
 From here, we clear the value of t.
 We have then:
 16t ^ 2 = 25&#10;&#10;t ^ 2 = 25/16
 We discard the negative root because we are looking for time:
 t =  \sqrt{ \frac{25}{16} } &#10;&#10;
 t =  \frac{5}{4}
 Answer:
 
it will take him to reach the ground about:
 
t = \frac{5}{4} seconds
5 0
3 years ago
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