Area of a circle = PI x r^2
Area of sheet = 22/7 x 18^2 = 1,018.29 square cm.
Area of small circle = 22/7 x 4.5^2 = 63.64 square cm.
There are 2 small circles so total area of the circles are 63.64 x 2 = 127.28 square cm.
Area of rectangle = l x w = 4 x 1 = 4 square cm.
Total area of cutouts = 127.28 + 4 = 131.28 square cm.
Area of sheet left, subtract area of cutouts fro area of sheet:
1018.29 - 131.28 = 887.01 square cm.
Round everything as needed.
Step 1) Graph the line y = (-1/2)x + 3. This line goes through (0,3) as its y intercept and it also goes through (2,2). You can start at (0,3) and move down one unit and to the right two units to arrive at (2,2). The slope of the boundary line is -1/2, meaning that the rise is -1 and the run is 2. A negative rise indicates we go down instead of up.
Step 2) Make the line in step 1 to be a dashed line. This is because there is no "or equal to" as part of the inequality sign. The dashed line says that points on this line are not part of the solution set.
Step 3) Shade above the dashed line. We shade above due to the "greater than" sign. Points above the dashed line are in the shaded solution set. An alternative is to test a point like (x,y) = (0,0) and you'll find y > (-1/2)x+3 turn into 0 > 3 which is a false statement; therefore, (0,0) is not in the solution set. This is expected as (0,0) is below the dashed line.
The final result is what you see in the attached image below. Points A and B help set up the dashed boundary line. Point C is the test point mentioned above which is not in the blue shaded solution region.
Note: the points shown in the diagram are optional when it comes to showing the final answer to your teacher. All you need really is the boundary line and its proper shaded region.
2•14 =28, 2• 270=540, 2•141=282, 2 is the GCF
Answer:
Just copy and paste the question and there will be at least 2 to 3 sites with the answer
Step-by-step explanation:
Answer:
- Let p be the population at t be the number of years since 2011. Then,

- The projected population of the high school in 2015=1800
- In <u>2019</u> the population be 1600 students
Step-by-step explanation:
Given: The population at Bishop High School students in 2011 =2000
Also, Every year the population decreases by 50 students which implies the rate of decrease in population is constant.
So, the function is a linear function.
Let p be the population at t be the number of years since 2011.
Then, 
So at t=0, p=2000
In year 2015, t=4, substitute t=4 in the above equation ,we get

Hence, the projected population of the high school in 2015=1800
Now, put p=1600 in the function , we get

Now, 2011+8=2019
Hence, in <u>2019</u> the population be 1600 students