Answer:
x = -15 and x = 1
Step-by-step explanation:
Since we have to use the complete the square method, we first need to <u>rewrite the equation</u> in the form 
.
This results in 
.
Next, we <u>simplify the equation</u> to get 
.
<u>Factoring </u>the left side gives us 
.
Finally we <u>solve the equations</u>: 
and 
.
This gives us x=1, and x=-15
Step-by-step explanation:
to compare them, we should all bring to the same denominator.
the lcm (lowest common multiplier) is the that denominator.
let's use the approach of the prime factors :
3 : 3
5 : 5
32 : 2×2×2×2×2
24 : 2×2×2×3
the lcm is the combination of the longest "streaks" of the prime factors.
so,
2×2×2×2×2 × 3 × 5 = 32×15 = 480
2/-3 = -2/3 = -320/480 (as 3×160 = 480)
-4/5 = -4×96 / 5×96 = -384/480 (as 5×96 = 480)
21/-32 = -21/32 = -315/480 (as 32×15 = 480)
-15/24 = -15×20 / 24×20 = -300/480 (24×20 = 480)
as
-384/480 < -320/480 < -315/480 < -300/480
we can say
-4/5 < -2/3 < -21/32 < -15/24
Answer:
80
Step-by-step explanation:
A certain company employs 6 senior officers and 4 junior officers. If a committee is to be created that is made up of 3 sr officers and 1 jr officer, how many different committees are possible?
8
24
58
80*
210
I initially got this one wrong, but after I saw the answer which is 80, I was able to solve it. But im not sure if this is the proper way of solving it, or if someone can suggest a more efficient way of solving it?
This is what I did, which was wrong:
Sr Officers + Jr Officers
(6!/3! 3! = 20) + (4!/3! = 4) = 24
It seems like the correct answer is:
Sr Officers X Jr Officers
(6!/3! 3! = 20) x (4!/3! = 4) = 80
If this is the most efficient way of solving, when do you know when to add them as opposed to multiplying them in this case?
