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guapka [62]
3 years ago
13

Which function is the inverse of f Superscript negative 1 Baseline (x) = negative one-fifth x minus four-fifths?

Mathematics
2 answers:
DedPeter [7]3 years ago
5 0

Answer:

f(x) = -5x - 4

Step-by-step explanation:

We want to get the inverse of the following function:

f^-1(x) = (-1/5)x - 4/5

To do that, we have to replace x with f(x) and f^-1(x) with x, as follows:

x = (-1/5)f(x) - 4/5

And then solve for f(x), the inverse of f^-1(x).

x + 4/5 = (-1/5)f(x)

f(x) = -5x + (-5)4/5

f(x) = -5x - 4

To check our result we compute a pair (x, f(x))

x   f(x)

1   -5*1 - 4 = -9

which has to be equivalent to (-9, 1) in the original function

x      f^-1(x)

-9     (-1/5)*(-9) - 4/5 = 1

Angelina_Jolie [31]3 years ago
3 0

Answer:

c on edge

Step-by-step explanation:

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True or false pls no guessing
marshall27 [118]

Answer:

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Step-by-step explanation:

5 X 5 X 5 = 125 because 5 X 5 would be 25. And 25 X 5 would be 125.

6 0
2 years ago
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Answer:

12 cups of mild

Step-by-step explanation:

3x3 is 9 and 3/4x9 is 12/4 so 3 9+3 is 12

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3 years ago
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Please Help! My question is in the picture.
Varvara68 [4.7K]
First we need to determine the type of progression in the question.
That's geometric progression. Because the pattern from one sequence to the others are about multiplying.

Second, determine the ratio of the progression
r = a₂/a₁
r = a₂ ÷ a₁
r = 1/2 ÷ 2
r = 1/2 × 1/2
r = 1/4

Third, determine the formula to know the recursive rule
a₂ = a × 1/4
a₂ = 1/4 × a
a_{n} =   \frac{1}{4} a_{(n-1)}

Fourth, determine a₁. a₁ is the first term of the progression
a₁ = 2

Final answer:
Recursive rule
a_{n} = \frac{1}{4} a_{(n-1)}
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4 0
3 years ago
Mike had 187 deer stickers. Mike gave 34 stickers to Sandy 79 stickers to his sister and additionally 49 stickers to Nancy. How
slamgirl [31]
Mike had 25 stickers left

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Find the perimeter and area of each figure.​
Sergio039 [100]

Answer:

  1. A = 2x; P = 4x+2. A = 4; P = 10.

  2. A = y² +2; P = 4y +2. A = 27; P = 22.

Step-by-step explanation:

1. The area is the sum of the marked areas of each of the tiles:

  A = x + x

  A = 2x

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The perimeter is the sum of the outside edge dimensions of the tiles. Working clockwise from the upper left corner, the sum of exposed edge lengths is ...

  P = 1 + (x-1) + x + 1 + (x+1) + x

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When x=2, these values become ...

  A = 2·2 = 4 . . . . square units

  P = 4·2+2 = 10 . . . . units

_____

2. Again, the area is the sum of the marked areas:

  A = y² + 1 + 1

  A = y² +2

__

The edge dimension of the square y² tile is presumed to be y, so the perimeter (starting from upper left) is ...

  P = y +(y-2) +1 +2 +(y+1) +y

  P = 4y +2

__

When y=5, these values become ...

  A = 5² +2 = 27 . . . . square units

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4 0
4 years ago
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