Question

Solve the system of equations below algebraically 2x-3y=8 4x+2y= 10

Answer 1

$2x - 3y = 8 \\ 4x + 2y = 10 \\ \\ - 4x + 6y = - 16 \\ \: \: 4x + 2y = 10 \\ \\ 8y = - 6 \\ y = \frac{ - 6}{8} = \frac{ - 3}{4} \\ \\ 4x - 2( \frac{ - 3}{4} ) = 10 \\ 4x + \frac{3}{2} = 10 \\ 4x = \frac{17}{2} \\ x = \frac{17}8$