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A company rents a biycycles for a fee of $10 plus $4 per hour of use. Write an algebraci expression for the total cost in dollar

ratelena [41]

The expression is 10 + 4h.

5 0

3 years ago

(50 points)There are x ducks in a pond. The number of swans in the pond is equal to the square root of the number of ducks. If t

RoseWind [281]

there are nine ducks and 3 swans

sqrt of 9 equals 3

3 + 9 = 12

6 0

3 years ago

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You have been hired as the quality control office of a pharmaceutical company that manufactures aspirin tablets. According to th

Firlakuza [10]

Answer:

$P(X=0)=(24C0)(0.04)^0 (1-0.04)^{24-0}=0.375413$

$P(X=1)=(24C1)(0.04)^1 (1-0.04)^{24-1}=0.$

So then the probability that the batch would be accepeted is:

$0.375413+0.375413=0.7508$

Step-by-step explanation:

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=24, p=0.04)$

On this case p=0.04 represent the probability that a random the tablet would be NOT accepted

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

They accept the batch if there is only one or no tablet that doesn’t meet the test specification, so let's find the individual probabilities for this case:

$P(X=0)=(24C0)(0.04)^0 (1-0.04)^{24-0}=0.375413$

$P(X=1)=(24C1)(0.04)^1 (1-0.04)^{24-1}=0.$

So then the probability that the batch would be accepeted is:

$0.375413+0.375413=0.7508$

3 0

3 years ago

Give some examples of quantities that increase or decrease at a constant rate expressed as a percent.

docker41 [41]

I would help but I'm not sure what you are asking for us to do

7 0

3 years ago

Read 2 more answers

The probability that aperson living in a certaincity owns a dog is estimated to be 0.3. Find the probabilitythat the tenth perso

allochka39001 [22]

The probability that the tenth person randomly interviewed in that city is the ﬁfth one to own a dog = 0.051

Given,

Consider the interview of a person is a trial.

Lets consider it success if a person owns a dog and consequently , a person without a dog will be a failure.'

Let the random variable X represent the number of persons to be interviewed to get 5 dog owner: in other words, to get 5 successors.

Probability of a success in each trial is p = 0.3. Therefore probability of a failure in each trial is q = 1 - p = 0.7 .

Because trials are independent. X has a negative binomial distribution with parameters k = 5, p = 0.3

P(X =x ) = b(x: k, p) = $[(x-1)(k-1)] p^kq^r^-^k$

where, x = k , k + 1 , k + 2......(1)

Now, Lets find the probability that the tenth person randomly interviewed in that city is the fifth one to own a dog

Using equation (1), we get:

P(X = 10) = b(10: 5, 0.3)

= [(10-1) (5 - 1)] $(0.3)^5(0.7)^1^0^-^5$

= [(9)(4)] $(0.3)^5(0.7)^1^0^-^5$

= 0.05146

Hence, The probability that the tenth person randomly interviewed in that city is the ﬁfth one to own a dog = 0.051

Learn more about Probability at:

brainly.com/question/743546

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4 0

1 year ago

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