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Find the range median first and third interquartile range for each data set

liraira [26]

Answer:

Range = 1.8

Median = 6.3

First Quartile = 6.3

Thrid Quartile = 6.8

Interquartile Range = 0.5

Step-by-step explanation:

First we need to arrange the data set from lowest to highest.

4.9, 5.8, 6.1, 6.2, 6.3, 6.3, 6.4, 6.6, 6.7, 6.7

To find the range of the data set, we simply take the highest value and subtract it to the lowest value.

Range = 6.7 - 4.9

Range = 1.8

To find the Median we need to get the middle number of the range. In this case there are two numbers in the middle of the set.

So we get both of them and get their average.

Median = 6.3 + 6.3 /2

Median = 6.3

To get the first quartile, we simply get the median of the lower of the data set.

4.9, 5.8, 6.1, 6.2, 6.3

The median of the first quartile is 6.1.

To get the third quartile, we get the median of the upper half of the data set.

6.3, 6.4, 6.6, 6.7, 6.7

The median of the third quartile is 6.6

To get the interquartile range, we need to subtract the median of the third quartile to the median of the first quartile.

Interquartile Range = 6.6 - 6.1

Interquartile Range = 0.5

Answer:

Range = 32

Median = 17.5

First Quartile = 15

Thrid Quartile = 19

Interquartile Range = 4

Step-by-step explanation:

First we need to arrange the data set from lowest to highest.

4, 9, 15, 16, 17, 18, 18, 19, 19, 36

To find the range of the data set, we simply take the highest value and subtract it to the lowest value.

Range = 36 - 4

Range = 32

To find the Median we need to get the middle number of the range. In this case there are two numbers in the middle of the set.

So we get both of them and get their average.

Median = 17 + 18 /2

Median = 17.5

To get the first quartile, we simply get the median of the lower of the data set.

4, 9, 15, 16, 17,

The median of the first quartile is 15.

To get the third quartile, we get the median of the upper half of the data set.

18, 18, 19, 19, 36

The median of the third quartile is 19.

To get the interquartile range, we need to subtract the median of the third quartile to the median of the first quartile.

Interquartile Range = 19 - 15

Interquartile Range = 4

6 0

3 years ago

Read 2 more answers

If F(x) = log 4 3x, find F -1(x). A.4^y=3x B.4^x=3y C.4^3y=x

lara31 [8.8K]

Answer:

${f}^{ - 1} (x) = \frac{{4}^{x} }{3}$

Step-by-step explanation:

The given logarithmic function is

$f(x) = log_{4}(3x)$

Let y=f(x)

This gives us:

$y = log_{4}(3x)$

We interchange x and y to get:

$x = log_{4}(3y)$

${4}^{x} = 3y$

$y = \frac{{4}^{x} }{3}$

Therefore the inverse is

${f}^{ - 1} (x) = \frac{{4}^{x} }{3}$

Based on the possible answers, B is most closed to the inverse.

The correct answer is B

5 0

3 years ago

A local agricultural cooperative claims that 55% of about 60,000 adults in a country believe that gardening should be part of th

insens350 [35]

Using the normal distribution and the central limit theorem, it is found that there is a 0.0409 = 4.09% probability that, from a simple random sample of 300 adults in the county, less than 50% would say they believe that gardening should be part of the school curriculum.

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

By the Central Limit Theorem, the sampling distribution of sample proportions for a proportion p in a sample of size n has $\mu = p, s = \sqrt{\frac{p(1 - p)}{n}}$

In this problem:

The proportion is of 55%, hence $p = 0.55$

The sample has 300 adults, hence $n = 300$

Then, the mean and the standard error are given by:

$\mu = p = 0.55$

$s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.55(0.45)}{300}} = 0.0287$

The probability is the p-value of Z when X = 0.5, hence:

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{0.5 - 0.55}{0.0287}$

$Z = -1.74$

$Z = -1.74$ has a p-value of 0.0409.

0.0409 = 4.09% probability that, from a simple random sample of 300 adults in the county, less than 50% would say they believe that gardening should be part of the school curriculum.

A similar problem is given at brainly.com/question/25800303

8 0

3 years ago

Find the equation of the line graphed below. Write the equation in the form y = mx + b and identify m and b m = b =

Alla [95]

ANSWER:

m = -3/4

b = -3