Question

The ear canal can be though of as a tube leading from the outer ear to the ear drum that is closed at one end. The typical length of an adult human ear canal is 2.5 cm. What is the fundamental resonant frequency of the ear canal? Assume the air inside it is at body temperature (37^\circ37 ​∘ ​​ C)

Answer 1

Answer:

3432 Hz.

Explanation:

The resonant frequency of the canal can be calculated as follows:

f = v/ 4l

Here, f is frequency, v is velocity of sound and l is the pipe length.

l = 2.5 cm = 0.025m and v = 343.2m/s.

Put these values to find the resonant frequency

f = 343.2 / 4 * 0.025.

f = 3432 Hz.

Thus, the answer is 3432 Hz.