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fenix001 [56]
4 years ago
14

Six friends share 5 small pizzas. Each friend first eats half of a pizza. How much more pizza does each friend need to eat to fi

nish all the pizzas and share them equally?
Mathematics
2 answers:
Pie4 years ago
6 0
1/2 I think because everybody already ate except for one person
Law Incorporation [45]4 years ago
4 0
If there were 5 small pizzas 2 friends eat 1 pizza so 6 friends eat 3 pizzas there will only be enough for 4 friends to eat so there would need to be 6 pizzas for each to be equally...
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What is the standard form polynomial representing the volume of this shipping container?
liq [111]

Answer:

Step-by-step explanation:

Volume of the shipping container = Lengt * Breadth * Height

Given

Length = 4x² + 3x

Breadth = x² – 8

Height = 6x +15

Volume of the container = ( 4x² + 3x)( x² - 8)(6x+15)

( 4x² + 3x)( x² - 8)  = 4x⁴-32x²+3x³-24x

( 4x² + 3x)( x² - 8) = 4x⁴+3x³-32x²-24x

(4x⁴+3x³-32x²-24x)(6x+15) = 24x⁵+60x⁴+18x⁴+45x³-192x³-480x²-144x²-360x

Collect like terms

( 4x² + 3x)( x² - 8)(6x+15) = 24x⁵+78x⁴-147x³-624x²-360x

Hence the standard form polynomial representing the volume of this shipping container is expressed as V = 24x⁵+78x⁴-147x³-624x²-360x

6 0
4 years ago
-2(3x-4)=4(5x-11) Solve for x
sveta [45]

-2(3x-4)=4(5x-11)

-6x+8=20x-44

8+44=26x

26x=52

x=52/26

your answer will be x=2

6 0
3 years ago
Read 2 more answers
The smallest whole number by which 9408 must be divided to get perfect square number
Snezhnost [94]

Answer:

9408,Is the only number that can divide into the same number to get exactly down to 1.

Step-by-step explanation:

4 0
3 years ago
Determine the location and values of the absolute maximum and absolute minimum for given function : f(x)=(‐x+2)4,where 0<×&lt
brilliants [131]

Answer:

Where 0 < x < 3

The location of the local minimum, is (2, 0)

The location of the local maximum is at (0, 16)

Step-by-step explanation:

The given function is f(x) = (x + 2)⁴

The range of the minimum = 0 < x < 3

At a local minimum/maximum values, we have;

f'(x) = \dfrac{(-x + 2)^4}{dx}  = -4 \cdot (-x + 2)^3 = 0

∴ (-x + 2)³ = 0

x = 2

f''(x) = \dfrac{ -4 \cdot (-x + 2)^3}{dx}  = -12 \cdot (-x + 2)^2

When x = 2, f''(2) = -12×(-2 + 2)² = 0 which gives a local minimum at x = 2

We have, f(2) = (-2 + 2)⁴ = 0

The location of the local minimum, is (2, 0)

Given that the minimum of the function is at x = 2, and the function is (-x + 2)⁴, the absolute local maximum will be at the maximum value of (-x + 2) for 0 < x < 3

When x = 0, -x + 2 = 0 + 2 = 2

Similarly, we have;

-x + 2 = 1, when x = 1

-x + 2 = 0, when x = 2

-x + 2 = -1, when x = 3

Therefore, the maximum value of -x + 2, is at x = 0 and the maximum value of the function where 0 < x < 3, is (0 + 2)⁴ = 16

The location of the local maximum is at (0, 16).

5 0
3 years ago
In the figure below, segment AC is congruent to segment AB.
jeyben [28]
<span>Triangle ACD is similar to triangle ABD</span>
8 0
3 years ago
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