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Svetlanka [38]
3 years ago
12

use the digits 3,1,8 and 4 to create four numbers. use each digit one time in, each number you create.

Mathematics
1 answer:
Simora [160]3 years ago
8 0
1834 is the first
3418 is the second
4813 is the third
8431 is the fourth
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Arnold's entire workout consisted of 10 minutes of warm up exercise, 25 minutes of lifting weights, and 15 minutes on the treadm
lord [1]

Add all the times together:

10 + 25 + 15 = 50 minutes total.

For the ratio divide the time for weights by total time:

25/50 which reduces to 1/2

The ratio is 1/2

5 0
3 years ago
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Q # 4 find the slope of the line through the pair of points A(2, -3), P(2, 9)
lutik1710 [3]
The answer is 12/0, which is undefined
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3 years ago
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What is the sum (Two-fifths x + StartFraction 5 over 8 EndFraction) + (one-fifth x minus one-fourth)?
liubo4ka [24]

The sum of  ( \frac{2}{5} x + \frac{5}{8} ) + ( \frac{1}{5} x - \frac{1}{4} ) is  \frac{3}{5} x +  \frac{3}{8}

Step-by-step explanation:

To add or subtract 2 fractions, they must have same denominators, if they not do that

  • Find the Lowest common multiple of the two denominators (LCM)
  • Replace each denominator by it
  • Divide The LCM by each denominator and multiply the numerator of each fraction by its quotient

∵ ( \frac{2}{5} x + \frac{5}{8} ) + ( \frac{1}{5} x - \frac{1}{4} )

- Let us start with adding the like terms

∴  ( \frac{2}{5} x + \frac{5}{8} ) + ( \frac{1}{5} x - \frac{1}{4} ) = (

∵ ( \frac{2}{5} x + \frac{1}{5} x ) have same denominators, then we can add them

∴ ( \frac{2}{5} x + \frac{1}{5} x ) = \frac{3}{5} x

∵  ( \frac{5}{8}  - \frac{1}{4} ) do not have the same denominators, then we must find

    LCM of 8 and 4

- The LCM of 8 and 4 is 8 because 8 is the first common multiple

   of 8 and 4

∵ LCM of 8 and 4 is 8

- Divide 8 by the denominator 4

∵ 8 ÷ 4 = 2

- Multiply the numerator of the fraction by 2

∴ \frac{1}{4}=\frac{2}{8}

∴  ( \frac{5}{8}  - \frac{1}{4} ) = ( \frac{5}{8} - \frac{2}{8} ) = \frac{3}{8}

∴  ( \frac{2}{5} x + \frac{5}{8} ) + ( \frac{1}{5} x - \frac{1}{4} ) = \frac{3}{5} x +  \frac{3}{8}

The sum of  ( \frac{2}{5} x + \frac{5}{8} ) + ( \frac{1}{5} x - \frac{1}{4} ) is  \frac{3}{5} x +  \frac{3}{8}

Learn more:

You can learn more about the fractions in brainly.com/question/2456302

#LearnwithBrainly

7 0
3 years ago
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PLS HELP ILL MARK BRAINLIST
Genrish500 [490]

Step-by-step explanation:

ok whats the question tell

6 0
3 years ago
How many extraneous solutions does the equation below have?
aev [14]

Answer:

A solution is said to be extraneous, if it is a zero of the equation, but it does not satisfy the equation,when substituted in the original equation,L.H.S≠R.H.S. 

The given equation consisting of  variable , m is

   \frac{2 m}{2 m+3} -\frac{2 m}{2 m-3}=1\\\\ 2 m[\frac{1}{2 m+3} -\frac{1}{2 m-3}]=1\\\\ 2 m\times \frac{[2 m-3 -2 m- 3]}{4m^2-9}=1\\\\ -6 \times 2 m=4 m^2 -9\\\\ 4 m^2 +1 2 m -9=0\\\\m=\frac{-12 \pm\sqrt{12^2-4 \times 4 \times (-9)}}{2\times 4}\\\\m=\frac{-12 \pm \sqrt {144+144}}{8}\\\\m=\frac{-12 \pm \sqrt {288}}{8}\\\\m=\frac{-12 \pm 12 \sqrt{2}}{8}\\\\m=\frac{3}{2}\times(-1 \pm \sqrt{2})

None of the two solution

m=\frac{3}{2}\times(-1 +\sqrt{2}) and , m=\frac{3}{2}\times(-1 -\sqrt{2}), is extraneous.

Here, L.H.S= R.H.S

Option A: 0→ extraneous

8 0
2 years ago
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