By measuring the width of the circle or sphere radius is half of the diameter
Answer:
x = -3
, y = 0
Step-by-step explanation:
Solve the following system:
{4 x - y = -12 | (equation 1)
-x - y = 3 | (equation 2)
Add 1/4 × (equation 1) to equation 2:
{4 x - y = -12 | (equation 1)
0 x - (5 y)/4 = 0 | (equation 2)
Multiply equation 2 by 4/5:
{4 x - y = -12 | (equation 1)
0 x - y = 0 | (equation 2)
Multiply equation 2 by -1:
{4 x - y = -12 | (equation 1)
0 x+y = 0 | (equation 2)
Add equation 2 to equation 1:
{4 x+0 y = -12 | (equation 1)
0 x+y = 0 | (equation 2)
Divide equation 1 by 4:
{x+0 y = -3 | (equation 1)
0 x+y = 0 | (equation 2)
Collect results:
Answer: {x = -3
, y = 0
First, we need to find the LCD (Least Common Denominator) so we can subtract them much easier.
An easy way to find the LCD is to just multiply the denominators together: So 2 • 5 = 10
We have to do the same to the numerators too though.
1/2 (5) = 5/10
2/5 (2) = 4/10
Now, the remade expression is:
5/10 - 4/10 which will equal 1/10.
Hope it helped! If it did, please mark as Brainliest! :)
15 - natural (1,2,3...15....) and integers (...-2,-1,0, 1,2,...15,...)
DATES: The rule amendments will become effective October 29, 1999. Section IV of this release contains information on compliance dates.
