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leva [86]
3 years ago
5

A variable whose value is less than zero is called ____________

Mathematics
1 answer:
pochemuha3 years ago
7 0
It is called a negative number. For example, -4   -976   -23   -21
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Monica’s retirement party cost two dollars, plus an additional three dollars for every guess she invites. If there are 16 guests
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Answer:

TWO BUCKS?? ballin on a budget

anyways, if there are 16 guests, the party would cost $50. sounds a lot more correct lol

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What is the slope of the line that passes through the points (8,-6) and (8,-9)
Alla [95]

Hope it helps.....................

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1 year ago
Expand (x-2)^7 using binomial theorem
Nastasia [14]

Answer:

x^7-14x^6+84x^5-280x^4+560x^3-672x^2+448x^2-128

Step-by-step explanation:

ends are x^7 and 120^7, and use the therom in the middle

5 0
3 years ago
Marla filled up her car's gas tank and then went on a trip. After she drove 329 miles, she filled her tank with 14 gallons of ga
romanna [79]

Answer:

23 1/2 miles per gallon

Step-by-step explanation:

We start with dividing 329 miles with 14 gallons because it asks to find the number of miles on each gallon of gas -

          Miles

-----------------------------     =

Each gallon of gas

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6 0
3 years ago
A manufacturing process produces semiconductor chips with a known failure rate of . If a random sample of chips is selected, app
AleksandrR [38]

Answer:

The probability that at least 14 of the chips will be defective is 0.6664.

Step-by-step explanation:

The complete question is:

A manufacturing process produces semiconductor chips with a known failure rate of 5.4%. If a random sample of 300 chips is selected, approximate the probability that at least 14 will be defective. Use the normal approximation to the binomial with a correction for continuity .

Solution:

Let <em>X</em> = number of defective chips.

The probability that a chip is defective is, <em>p</em> = 0.054.

A random sample of <em>n</em> = 300 chips is selected.

A chip is defective or not is independent of the other chips.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 300 and <em>p</em> = 0.054.

But the sample selected is too large.

So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  1. np ≥ 10
  2. n(1 - p) ≥ 10

Check the conditions as follows:

 np=300\times 0.054=16.2>10\\n(1-p)=300\times (1-0.054)=283.8>10

Thus, a Normal approximation to binomial can be applied.

So,  X\sim N(\mu =16.2,\ \sigma^{2}=15.3252).

Compute the probability that at least 14 of the 300 chips will be defective as follows:

Use continuity correction:

P (X ≥ 14) = P (X > 14 + 0.50)

               = P (X > 14.50)

               =P(\frac{X-\mu}{\sigma}>\frac{14.50-16.20}{\sqrt{15.3252}})

                =P(Z>-0.43)\\=P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that at least 14 of the chips will be defective is 0.6664.

5 0
3 years ago
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