Hello :
f(x) = <span>a(x-k)²+k....... the point vertex is (h , k )
in this exercice : h = -3 and k = -1 s0 f(x) = a(x+3)²-1
find : a
but f(0)=8
a(0+3)² -1 = 8
9a-1=8
9a =9
a=1
f(x) =(x+3)²-1 =x²+6x+9-1
f(x) = x²+6x+8 .... (</span><span>the quadratic function in standard form )</span>
Answer:
3/8 (Decimal: 0.375)
Step-by-step explanation:
Answer:
a/sinA = b/sinB = c/sinC
Step-by-step explanation:
This sequence has generating function
(if we include 
for a moment)
Recall that for 
, we have
Take the derivative to get
Take the derivative again:
Take the derivative one more time:
so we have
