1/10 for Hugh to be first and after he is picked only 9 students remain so 1/9 for stu and after he is picked only 8 remain to be chosen so 1/8 for lou. The chance of all three happening is 1/10×1/9×1/8=1/720 this is the probability that 3 triplets will be chosen in that exact order out of 10 students
Answer:
6.167
Step-by-step explanation:
1 + 2/3 - (-9/2)
1 + 2/3 + 9/2
Taking LCM (1 x 2 x 3)
6/6 + 4/6 + 27/6
6 + 4 + 27/6
37/6
6.167 Ans
Answer:
ok
Step-by-step explanation:
1) x=-17
2) -1=x
3) (sorry don't know)
4) x=-20
Answer:
Solution will be 1/15625
Step-by-step explanation:
Substitute the value of first term for ar^(4-1) for the third term with 1/25 on RHS, make r the subject (which is the common ratio)
you'll get r as 1/5
Now for the eighth term, replace the "4" in the formula with "8" and a with "5" and observe the magic.
