Let’s assume that Laura has x$
Jose = 8+ x
Keith= 3x
So the total is equal to
118= x + 8 +x + 3x
118= 5x + 8
Subtract 8 from both sides
110= 5x
Divide 5 by both sides
22$= x which is what Laura has
Jose will have :8+22= 30$
Keith will have :3*22=66$
Example:
The sum of two consecutive integers is -15. What is the product of the two integers?
x = 1st consecutive integer
x + 1 = 2nd consecutive integer {consecutive integers increase by 1}
x + x + 1 = -15 {the sum of two consecutive integers is -15}
2x + 1 = -15 {combined like terms}
2x = -16 {subtracted 1 from each side}
x = -8 {divided each side by 2}
x + 1 = -7 {substituted -8, in for x, into x + 1}
-8 and -7 are the two consecutive integers
Their product is 56.
Yes, it is fairly reasonable... if you round it..
however, if you want exact calculations, then it might not be so reasonable, because it will go over the total amount
so if you round it, then yes it is fairly reasonable
Step-by-step explanation:
I'm guessing this is competing the perfect square
so it's 56
