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3 years ago

Which graph shows negative acceleration?

Physics

2 answers:

castortr0y [4]3 years ago

5 0

B because negative acceleration means it would go down

pochemuha3 years ago

5 0

Answer:

Its D. I did it in 2020 on edgenuity

Explanation:

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A positive point charge Q1 = 2.5 x 10-5 C is fixed at the origin of coordinates, and a negative point charge Q2 = -5.0 x 10-6 C

mario62 [17]

Answer:

3.62 m and - 1.4 m

Explanation:

Consider a location towards the positive side of x-axis beyond the location of charge Q₂

x = distance of the location from charge Q₂

d = distance between the two charges = 2 m

For the electric field to be zero at the location

E₁ = Electric field by charge Q₁ at the location = E₂ = Electric field by charge Q₂ at the location

$\frac{kQ_{1}}{(2 + x)^{2}}= \frac{kQ_{2}}{x^{2}}$

$\frac{2.5\times 10^{-5}}{(2 + x)^{2}}= \frac{5 \times 10^{-6}}{x^{2}}$

x = 1.62 m

So location is 2 + 1.62 = 3.62 m

Consider a location towards the negative side of x-axis beyond the location of charge Q₁

x = distance of the location from charge Q₁

d = distance between the two charges = 2 m

For the electric field to be zero at the location

E₁ = Electric field by charge Q₁ at the location = E₂ = Electric field by charge Q₂ at the location

$\frac{kQ_{1}}{(x)^{2}}= \frac{kQ_{2}}{ (2 + x)^{2}}$

$\frac{2.5\times 10^{-5}}{(x)^{2}}= \frac{5 \times 10^{-6}}{(2+x)^{2}}$

x = - 1.4 m

6 0

4 years ago

A sled is initially given a shove up a frictionless 37.0 ∘ incline. It reaches a maximum vertical height 1.20 m higher than wher

labwork [276]

The initial speed of the sled at the given height is 4.85 m/s.

<h3>Initial speed of the sled</h3>

Apply the principle of conservation of energy;

K.E = P.E

¹/₂mv² = mgh

v² = 2gh

v = √2gh

where;

h is the vertical height reached
g is acceleration due to gravity

v = √(2 x 9.8 x 1.2)

v = 4.85 m/s

Thus, the initial speed of the sled at the given height is 4.85 m/s.

Learn more about initial speed here: brainly.com/question/24493758

#SPJ1

5 0

2 years ago

point) A tank in the shape of an inverted right circular cone has height 5 meters and radius 4 meters. It is filled with 4 meter

zysi [14]

Answer:

W = 907963.50 J = 907.96 J

Explanation:

Note: Refer to the figure attached

Now, from the figure we have similar triangles ΔAOB and ΔCOD

we have

$\frac{5}{4}=\frac{x}{r}$

$r=\frac{4x}{5}$

Now, the work done to empty the tank can be given as:

$W = \int\limits^4_0 {(5-x)\rho\times g A} \, dx$

$W = \int\limits^4_0 {(5-x)1080\times 9.8 (\pi r^2)} \, dx$

$W = \int\limits^4_0 {(5-x)\times10584\times (\pi (\frac{4x}{5})^2)} \, dx$

$W = 6773.76\pi\int\limits^4_0 {(5-x)x^2)} \, dx$

$W = 6773.76\pi[\frac{5}{3}x^3-\frac{1}{4}x^4]^4_0$

$W = 6773.76\pi[\frac{128}{3}]$

W = 907963.50 J = 907.96 J

7 0

3 years ago

A copper wire has a diameter of 1.02mm and carries

Nostrana [21]

Explanation:

area = a

density × vd × q × area = I

and J = I /A

(current density)

7 0

4 years ago

Question 2:

Vesna [10]

Explanation:

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3 0

3 years ago

Read 2 more answers