The velocity of a particle moving along the x axis is given by vx = a t − b t3 for t > 0 , where a = 27 m/s 2 , b = 3.1 m/s 4
1 answer:
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Answer:
a) 0.3 m
b) r = 0.45 m
Explanation:
given,
q₁ = 0.44 n C and q₂ = 11.0 n C
assume the distance be r from q₁ where the electric field is zero.
distance of point from q₂ be equal to 1.8 -r
now,
E₁ = E₂
1.8 = 6 r
r = 0.3 m
<h3>b) zero when one charge is negative.</h3>let us assume q₁ be negative so, distance from q₁ be r
from charge q₂ the distance of the point be 1.8 +r
now,
E₁ = E₂
1.8 =4 r
r = 0.45 m
Answer:
Explanation:
Acceleration can be found by dividing the change in velocity by the time.
where Vf is the final velocity, Vi is the initial velocity, and t is the time.
Since the car came to a complete stop, it's final velocity was 0 meters per second.
The initial velocity was 22 meters per second.
The time was 2.0 seconds.
Substitute the values into the formula.
Subtract in the numerator first.
- 0 m/s- 22 m/s = -22 m/s
Divide.
The acceleration of the car was -11 meters per square second. The negative acceleration indicates slowing down/stopping.
(A)
The energy stored by the system is given by
where
P is the power provided
t is the time elapsed
In this case, we have
P = 60 kW = 60,000 W is the power
t = 7 is the time
Therefore, the energy stored by the system is
(B) 4830 rad/s
The rotational energy of the wheel is given by
(1)
where
is the moment of inertia
is the angular velocity
The moment of inertia of the wheel is
where M is the mass and R the radius of the wheel.
We also know that the energy provided is
So we can rearrange eq.(1) to find the angular velocity:
(C)
The centripetal acceleration of a point on the edge is given by
where
is the angular velocity
R = 0.12 m is the radius of the wheel
Substituting, we find