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3 years ago

Area of rectangle is 5.68 sq cm length 0.4 cm. What is side length?

Mathematics

1 answer:

Alenkinab [10]3 years ago

6 0

Answer:

If the Area is 5.68 then you have to dived 0.4 then you will get as your width 14.2

Step-by-step explanation:

L× W= A

and now

A÷L=W

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Here a subtraction problem that has been solved incorrectly what is the right way 74-25=59

jek_recluse [69]

Answer:

74-25 is 49

Step-by-step explanation:

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2 years ago

susan englared a rectangle with a height of 3cm and length of 10cm on her computer. The length of the new rectangle is 15cm.Find

ExtremeBDS [4]

$\frac{3}{x} \times \frac{10}{15}$
when you cross multiply the answer is 4.5

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3 years ago

Yupin is making fruit punch. The recipe calls for 2 ½ of guava juice. The guava juice container has 4 ¼ cups of juice in it. How

astraxan [27]

Answer:

1 $\frac{3}{4}$ cups

Step-by-step explanation:

Convert the numbers to decimals, then subtract the amount needed from the amount in the juice container:

4.25 - 2.5

= 1.75

This is equivalent to the fraction 1 $\frac{3}{4}$

So, after Yupin makes the punch, there will be 1 $\frac{3}{4}$ cups of guava juice left in the container

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3 years ago

Mr. Anderson paid $19.18 for a CD cover. This amount included a tax of 2%. What was the cost of the CD cover before tax

uysha [10]

The price is around 18.80

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3 years ago

Suppose $1000 is invested at a rate of 13% per year compounded monthly. (Round your answers to the nearest cent.)

masya89 [10]

Answer:

a. $1010.83

b.$1066.77

c. $1138.00

d.$13,269.22

Step-by-step explanation:

Given the annual rate as 13%(compounded monthly) and the principal amount as $1000.

a. #first we calculate the effective annual rate;

$i_m=(1+i/m)^m-1\\\\i_{12}=(1+0.13/12)^{12}-1=0.1380$

The compounded amount after 1 month is therefore:

$P_1=P(1+I_m)^n, n=1/12, i_m=0.1380, P=1000\\\\P_1=1000(1+0.1380)^{1/12}\\\\P_1=1010.83$

Hence, the principle after one month is $1010.83

b. The principal after 6 months:

-From a above we have the effective annual rate as 0.1380 and our time is 6 months:

$P_{6m}=P(1+i_m)^n, \ n=6m, P=1000, i_m=0.1380\\\\P_{6m}=1000(1+0.1380)^{6/12}\\\\=1066.77$

Hence, the principal after 6 months is $1066.77

c.The principal after 1 year:

-From a above we have the effective annual rate as 0.1380 and our time is 12 months:

$P_{1y}=P(1+I_m)^n, n=1/12, i_m=0.1380, P=1000\\\\P_{1y}=1000(1+0.1380)^{12}\\\\P_{1y}=1138$

Hence, the principal after 1 year is $1138.00

d. The principal after 20years:

-From a above we have the effective annual rate as 0.1380 and our time is 20yrs:

$P_{20y}=P(1+I_m)^n, n=1/12, i_m=0.1380, P=1000\\\\P_{20y}=1000(1+0.1380)^{12}\\\\P_{20y}=13269.22$

Hence, the principal after 20 years is $13,269.22

3 0

3 years ago