Answer:
Well, in reality, all circles are similar to each other. They will all have the same angles, and they don't really have side lengths. So, they are similar.
But to PROVE they are similar, we will transform Circle C to match circle E.
Circle C has a center at (-3, 1), and Circle E has a center of (4, 9). For Circle C to have the same center as Circle E, we will translate Circle C 7 units to the right, and 8 units up.
Since Circle C has a radius of 4, and Circle E has a radius of 3, dilate Circle C by a factor of 3/4. That way, the radius is 3 units as well.
And there you go! The two circles will map perfectly on top of each other.
Hope this helps!
It looks correct to me :)
Line D and C because they are not parallel but distorted or unsymmetrical
There are two -main- approaches to answer this problem. By using the sine identity, or applying law of sines.
We'll do the sine trig. identity, as it is the most effective.
Given an angle '

' in a right triangle, '

' is defined as the opposite side of the triangle to the given angle, over the triangle's hypotenuse.
So, for this setup:

Now, we solve for x:
So, answer is 3.4
Consider the following two ordered bases of R2 R2: BC=={⟨1,2⟩,⟨3,5⟩},{⟨−1,1⟩,⟨1,−2⟩}. B={⟨1,2⟩,⟨3,5⟩},C={⟨−1,1⟩,⟨1,−2⟩}. Find th
Tamiku [17]
Answer:
This question is maybe r2+ =>()0?
Step-by-step explanation: