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3 years ago

11

if you can give me equations with the varbile x on both sides that equal 16 you can have my points and ill help you also so what

is an equation that x=16

1 answer:

pshichka [43]3 years ago

3 0

I'm not sure if this is what you wanted, but here:

-8x+11 = 8x-5

-> Solving this gives you x = 16

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Please help me!! I’m bad at math!!

tatyana61 [14]

Answer:

50.24

-

And, you're not bad at math! You goot this correct! :)

Step-by-step explanation:

c=25.12

we can use this to find the raidus!

-

plug it back into the circumference formula first.

c=(pi)(d)

25.12=3.14*d

divide both sides by 3.14!

d=8 but we need the radius, so we just divide by 2. 8/2 = 4. so the raidus is 4!

-

now we plug it into the area of a circle formula.

π · r2

3.14 * 4^2

3.14*16

50.24

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2 years ago

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fenix001 [56]

I’m pretty sure it is a

4 0

3 years ago

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The following image is a function.

Alborosie

That is going to be false

6 0

2 years ago

23) 874<br><br><br><br><br>I need help

AVprozaik [17]

Answer: 20102

Step-by-step explanation: 23 x 874 =20102

6 0

2 years ago

the verticales of triangle XYZ are X(-3,-6),Y(21,-6),and Z(21,4). What is the perimeter of the triangle

andrezito [222]

Answer:

<h2>P = 60</h2>

Step-by-step explanation:

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

X(-3, -6), Y(21, -6). Substitute:

$XY=\sqrt{21-(-3))^2+(-6-(-6))^2}=\sqrt{24^2+0^2}=\sqrt{24^2}=24$

X(-3, -6), Z(21, 4). Substitute:

$XZ=\sqrt{(21-(-3))^2+(4-(-6))^2}=\sqrt{24^2+10^2}=\sqrt{576+100}=\sqrt{676}=26$

Y(21, -6), Z(21, 4). Substitute:

$YZ=\sqrt{(21-21)^2+(4-(-6))^2}=\sqrt{0^2+10^2}=\sqrt{10^2}=10$

The perimeter of the triangle XYZ:

$P_{\triangle XYZ}=XY+XZ+YZ$

Substitute:

$P_{\triangle XYZ}=24+26+10=60$

6 0

2 years ago