This one is prime. The sum of two squares doesn't factor.
The more interesting case is q^2-1, which factors into (q-1)(q+1).
In this question weight of a flea and an ant is given, but their units are different. So comparing and finding out the weight of flea and ant would be difficult. First thing that needs to be done is to bring the units of both the flea and the ant under same unit.
Weight of flea = 8 decigrams
Weight of ant = 3 milligrams.
Now let us convert the weight of the flea from decigrams to milligrams.
We already know that
1 decigram = 100 milligram
Then
8 decigrams = 100 * 8 milligrams
= 800 milligrams
Then
The weight by which the flea is greater than the ant = (800 - 3) milligrams
= 797 milligrams.
So the flea weighs 797 milligrams more than the ant.
Answer:
638
Step-by-step explanation:
1. Isolate the variable 881 = k - (-243)
-243 -243
2. combine like terms 881 - 243 = k
3. answer 638
Answer:
-3,694
I am not sure what in the world the rest means, so I am very sorry. I just subtracted some stuff. I have no clue if that helped...
Answer:
your answer is correct
Step-by-step explanation:
4b² + 8b + 3
Consider the factors of the product of the coefficient of the b² term and the constant term which sum to give the coefficient of the b- term.
product = 4 × 3 = 12 and sum = + 8
The factors are 2 and 6
Use these factors to split the b- term
4b² + 2b + 6b + 3 ( factor the first/second and third/fourth terms )
= 2b(2b + 1) + 3(2b + 1) ← factor out (2b + 1) from each term
= (2b + 1)(2b + 3)
