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Klio2033 [76]
3 years ago
13

Suppose we are testing the null hypothesis H 0 mu=20 and the alternative H iu =20 , normal population with sigma=6 A random samp

le of nine observations are drawn from the population, and we find the sample mean of these observations x = 17 The value of the test statistic z is approximatel
Mathematics
1 answer:
cupoosta [38]3 years ago
8 0

Answer:

The value of the test statistic is z = -1.5

Step-by-step explanation:

The formula for the test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the statistic, \mu is the mean, \sigma is the standard deviation and n is the number of observations.

In this problem, we have that:

\mu = 20, X = 17, \sigma = 6, n = 9

So

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{17 - 20}{\frac{6}{\sqrt{3}}}

z = -1.5

The value of the test statistic is z = -1.5

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2 years ago
If a=2b^3 and b= -1/2c ^-2,express a in terms of c.
ElenaW [278]

Answer:

Part 1) a=-\frac{1}{4c^6}

Part 2) a=-\frac{1}{4c^{-6}}

Step-by-step explanation:

Part 1) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2}c^{-2} ----> equation B

substitute equation B in equation A

a=2(-\frac{1}{2}c^{-2})^{3}

Applying property of exponents

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therefore

a=-\frac{1}{4c^6}

Part 2) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2} ----> equation B

substitute equation B in equation A

a=2(-\frac{c^{2}}{2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

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Answer:I hope the following example will help you

Step-by-step explanation:

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