A rectangular painting measures 15 inches by 18 inches and contains a frame of uniform width around the four edges. The perimete
r of the rectangle formed by the painting and its frame is 90 inches. Determine the width of the frame.
1 answer:
Answer:
3 inches
Step-by-step explanation:
Lenght = 18 inches
Width =15 inches
Perimeter of the rectangular painting and frame = 90 inches
Let X be the width of the frame
The width of the framed picture = 15 + 2x
The length of the framed picture = 18 + 2x
Perimeter = 2 (L + W)
90 = 2(15 + 2x + 18+ 2x)
90 = 2(33 + 4x)
90 = 66 + 8x
8x = 90 - 66
8x = 24
x = 24/8
x = 3 inches
the width of the frame is 3 inches
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D. Corresponding.
Step-by-step explanation:
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<u>Exterior angles</u> would be where they are placed in the drawing you provided now, except alternate exterior angles would be on alternating sides of that significant diagonal line. A picture is attached and shows what b. alternate exterior might look like.
<u>Vertical angles</u> appear on opposing sides. This one is hard to word, but I will attach a picture if it allows me to. You see in your picture where the top orange line is resting? Jump across that line. Jump one down in that little acute angle place that is still touching the top horizontal line. This is where you would have had to place your bottom orange angle to make it vertical.
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