A rectangular painting measures 15 inches by 18 inches and contains a frame of uniform width around the four edges. The perimete
r of the rectangle formed by the painting and its frame is 90 inches. Determine the width of the frame.
1 answer:
Answer:
3 inches
Step-by-step explanation:
Lenght = 18 inches
Width =15 inches
Perimeter of the rectangular painting and frame = 90 inches
Let X be the width of the frame
The width of the framed picture = 15 + 2x
The length of the framed picture = 18 + 2x
Perimeter = 2 (L + W)
90 = 2(15 + 2x + 18+ 2x)
90 = 2(33 + 4x)
90 = 66 + 8x
8x = 90 - 66
8x = 24
x = 24/8
x = 3 inches
the width of the frame is 3 inches
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The average number of packages the led to be selected in order to find a package that was not delivered on time is 2.2 option first is correct.
<h3>What is simple random sampling?</h3>With simple random sampling, each component of the population has an equal chance of being selected for the sample.
The question is incomplete.
The complete question is in the picture, please refer to the attached picture.
We have:
A shipping company claims that 95% of packages are delivered on time.
From the table:
00- 04 is the package not delivered on time.
05-99 - package delivered on time.
The first simulation's third number, 31, 64, 04, is where you can locate an item that wasn't delivered on time.
The second simulation's second number, 34, 02, is the location of a late-delivered delivery.
The third simulation is equal to 96,00 - the second number, which is the location of a late package.
The second number where to find a shipment not delivered on time in the fourth simulation is 31,04
Where to find a box that wasn't delivered on time in the fifth simulation: 98, 01, second number
The average number = (3 + 2 + 2 + 2 + 2)/5
= 11/5
= 2.2
Thus, the average number of packages the led to be selected in order to find a package that was not delivered on time is 2.2 option first is correct.
Learn more about the simple random sampling here:
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