Answer:
14.65
Step-by-step explanation:
You add 13 + 6 3/4 then subtract 5 1/10 from that and you have your answer.
At the beginning, there are 15 pigs without ribbons. one of the pigs receives a ribbon. how many are left ribbonless?
<span>14. when another pig is given a ribbon, there are 13 left. after all the ribbons have been given out, 3 of the 15 pigs have ribbons. </span>
<span>if any one of the 15 at the beginning is given a ribbon, there are 15 possible combos. for the second ribbon, there are 14 combos- but each of those combos has to go through the first 15. for the third ribbon, there are 13 combos, going through 14 and 15. </span>
<span>simply put, 15 x 14 x 13.</span>
0.125 the first one, even though im not sure.
T= 39
W= 0.1
Hope this helps!
Not too sure but I think it’s A. Linear Trinomial
Hope it helps!
