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barxatty [35]
3 years ago
14

Find the possible value or values of y in the quadratic equation 4 – 4y – y 2 = 0. A. y = –3, y = –1 B. y = 2 C. y = –2 + 2√ 2,

y = −2 − 2√ 2 D. y = –4, y = 1
Mathematics
1 answer:
xz_007 [3.2K]3 years ago
8 0
  4 - 4y - y² = 0
-y² - 4y + 4 = 0
y = -(-4) ± √((-4)² - 4(4)(-1))
                    2(-1)
y = 4 ± √(16 + 16)
               -2
y = 4 ± √(32)
          -2
y = 4 ± 4√(2)
         -2
y = 4 + 4√(2)    or    y = 4 - 4√(2)
          -2                            -2
y = -2 - 2√(2)    or    y = -2 + 2√(2)

The answer is C.
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