The series converges to 1/(1-9x) for -1/9<x<1/9
Given the series is ∑ 
We have to find the values of x for which the series converges.
We know,
∑ 
converges to (a) / (1-r) if r < 1
Otherwise the series will diverge.
Here, ∑ 
is a geometric series with |r| = | 9x |
And it converges for |9x| < 1
Hence, the given series gets converge for -1/9<x<1/9
And geometric series converges to a/(1-r)
Here, a = 1 and r = 9x
Therefore, a/(1-r) = 1/(1-9x)
Hence, the given series converges to 1/1-9x for -1/9<x<1/9
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Answer:
Step-by-step explanation:
a). There are 8 points in the figure attached.
b). There are 9 lines in the given figure.
c). There are 5 planes in the figure attached.
d). Three collinear points are D,G and F.
e). Four co-planar points are G, F, H and C.
f). Intersection of planes ABC and ABE is the common line AB.
g). Intersection of planes BCH and DEF is the common line EF.
h). Intersection of AD and DF is a point D.
Answer:
31 children and 290 adults
Step-by-step explanation:
Let a = number of adults and c = number of children.
a + c = 321
2a + 1.75c = 634.25
Multiply both sides of the the first equation by -2 and add it to the second equation.
-2a - 2c = -642
(+) 2a + 1.75c = 634.25
--------------------------------------
-0.25c = -7.75
Divide both sides by -0.25
c = 31
Use the first equation to find a.
a + c = 321
Substitute 31 for c.
a + 31 = 321
Subtract 31 from both sides.
a = 290
Answer: 31 children and 290 adults
