I believe the equation is
![4 \sqrt[4]{2x} + 6 \sqrt[4]{2x}](https://tex.z-dn.net/?f=4%20%5Csqrt%5B4%5D%7B2x%7D%20%2B%206%20%20%5Csqrt%5B4%5D%7B2x%7D%20)
In this case, you would simplify it by adding them together.
![4 \sqrt[4]{2x} + 6 \sqrt[4]{2x}](https://tex.z-dn.net/?f=4%20%5Csqrt%5B4%5D%7B2x%7D%20%2B%206%20%20%5Csqrt%5B4%5D%7B2x%7D%20)
=
![10 \sqrt[4]{2x}](https://tex.z-dn.net/?f=10%20%20%5Csqrt%5B4%5D%7B2x%7D%20)
And can even be changed to an exponential equation:
Answer:
Step-by-step explanation:
The mode is the number of most repeated data in the set.
Given set 2, 1, 4, 7, 1 has mode 1 (repeated twice).
If we add 1 to the set the mode will remain 1 as it will repeat three times, so the mode won't change.
There is no change in mode, so the mode decrease is zero.
Answer:
In this, 3.695 to 4, the tenths was rounded
Step-by-step explanation:
Answer:
15
Step-by-step explanation:
3^2 + sqrt4 + 4
3^2 = 9
sqrt4 = 2
(9)+(2)+(4)=15
therefore, the answer is 15