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mart [117]
2 years ago
5

What is the solution to 2x + 8 > 10 ?

Mathematics
1 answer:
djyliett [7]2 years ago
6 0
2x + 8 > 10
You first move + 8 to the other side, so you subtract 8
(When you see addition, you perform subtraction)
2x + 8 - 8  > 10 - 8
+ 8 and - 8 cancels out
2x > 2
Now, to isolate x, you should divide both sides by 2
(When you see multiplication, you perform division)
\frac{2x}{2} > \frac{2}{2}
2 and 2 cancels out and we are left with
x > 1
So your final answer will be x > 1
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Answer:

We just need to evaluate and get f(2i)=0, f(-2i)=0.

Step-by-step explanation:

Since i^2=-1, then i^3=i^2i=-i, and we can apply this when we evaluate f(x) =x^3 + 4x for 2i and -2i.

First we have:

f(2i) =(2i)^3 + 4(2i)=2^3i^3+8i=8(-i)+8i=0

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Then we have:

f(-2i) =(-2i)^3 + 4(-2i)=(-2)^3i^3-8i=-8(-i)-8i=8i-8i=0

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4 0
3 years ago
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2 years ago
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I need this fast thank you! :)
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Answer:

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Step-by-step explanation:

Hope this helps! Good Luck!

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