4 years ago

Is the 0.45 square root greater or lesser than 0.229

1 answer:

liq [111]4 years ago

3 0

Squire root of 0.45 is 0.67 so it is less than 0.229

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romanna [79]

Answer:

Step-by-step explanation:

$\sqrt{-64}$ and $\sqrt{-16}$ can be expressed in complex form, with $\sqrt{-1}$ = i

$\sqrt{-64}$ = $\sqrt{64(-1)}$ = $\sqrt{64}$ × $\sqrt{-1}$ = 8i

$\sqrt{-16}$ = $\sqrt{16(-1)}$ = $\sqrt{16}$ × $\sqrt{-1}$ = 4i

the factors can then be expressed as

(6 + 8i)(3 - 4i) ← expand using FOIL

= 18 - 24i + 24i - 32i² [ i² = ( $\sqrt{-1}$ )² = - 1 ]

= 18 - 24i + 24i + 32 ← collect like terms

= 18 + 32 + 0

= 50

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ollegr [7]

Lin has a 2/40 chance of winning,

or in percentage, a 2.5% chance.

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