Answer:
B. x<27
Step-by-step explanation:
The shelter has 165 animals.
The shelter must keep its total occupancy below 300.
The shelter takes in an average of 5 animals per day. If x is the number of days, then in x days the shelter takes 5x animals. In total there will be
165+5x animals. This number must be less than 300, so
Answer:
Step-by-step explanation:
Lateral surface area of the triangular prism = Perimeter of the triangular base × Height
By applying Pythagoras theorem in ΔABC,
AC² = AB² + BC²
(34)² = (16)² + BC²
BC =
=
= 30 in.
Perimeter of the triangular base = AB + BC + AC
= 16 + 30 + 34
= 80 in
Lateral surface area = 80 × 22
= 1760 in²
Total Surface area = Lateral surface area + 2(Surface area of the triangular base)
Surface area of the triangular base =
=
= 240 in²
Total surface area = 1760 + 2(240)
= 1760 + 480
= 2240 in²
Volume = Area of the triangular base × Height
= 240 × 20
= 4800 in³
Answer:
hello your question is incomplete attached below is the complete question
estimating: Ft( -15,40 ) = ( 1.2 + 1.4 ) / 2 = 1.30⁰c
when the actual temperature is -15⁰c and the wind speed is 40 km/h the apparent temperatures increase by 1.3⁰c that the actual temperature rises
estimating: Fv ( -15,40 ) = (-0.2 + -0.1 ) / 2 = -0.15⁰c
when the actual temperature -15⁰c and the wind speed is 40 km/h the apparent temperature decreases by about 0.15⁰c for every km/h that the wind speed
Step-by-step explanation:
A) Estimating the values of Ft(−15, 40) and fv(−15, 40)
attached below is a detailed solution
To estimate the value of Ft( -15,40 ) we have to take an average value hence Ft ( -15,40 ) = ( 1.2 + 1.4 ) / 2 = 1.30
and this means that when the actual temperature is -15⁰c and the wind speed is 40 km/h the apparent temperatures increase by 1.3⁰c that the actual temperature rises
To estimate the value of Fv(-15,40 ) we have to take an average value
hence Fv ( -15,40 ) = (-0.2 + -0.1 ) / 2 = -0.15
and this means that when the actual temperature -15⁰c and the wind speed is 40 km/h the apparent temperature decreases by about 0.15⁰c for every km/h that the wind speed
