All categories

3 years ago

What is the value of a3 in the sequence?

2 answers:

Studentka2010 [4]3 years ago

7 0

Basically, we are trying to find the third number in the pattern. The pattern is - -4, -2, -12, -14 and so on. We can see that the third number is -12, which is a₃. Therefore, the answer is C) -12. Hope this helped!

nika2105 [10]3 years ago

6 0

Answer:

C.)-12

Step-by-step explanation:

A sequence is an ordered list of numbers.

One way to define the sequence is by listing the numbers of the sequence.

This list is

a1,a2,a3,a4,a5, ... ,an

Where a1 is the first number of the sequence, a2 is the second number of the sequence , ... , an is the ''nth'' number of the sequence meaning that the sequence has a total of ''n'' numbers.

In this exercise, the sequence is

-4,-2,-12,-14,...

This means that the first number of the sequence is -4 ⇒ a1 = -4

The second number is -2 ⇒ a2 = -2

The third number is -12 ⇒ a3 = -12

The value of a3 in the sequence is -12

The correct option is C.)-12

You might be interested in

Factor: m^2 - 20m - 21

Anton [14]

Answer: (m-21)(m+1)

Step-by-step explanation:

To factor this trinomial, find two numbers that multiply to -21 and add to -20:

(-21)(1)=-21

-21+1=-20

They are -21 and 1.

Add -21 and 1 to m to get both factors:

(m+(-21)) and (m+1)

(m-21) and (m+1)

Multiply them to get the answer:

(m-21)(m+1)

4 0

3 years ago

gallons of water can fill a pool that is 50 yards by 20 yards and is 9 feet deep? (Assume 7 1/2 gallons per cubic foot.)

saul85 [17]

L = 50 yards or 150 feet W = 20 yards or 60 feet H = 9 feet V = 150 * 60 * 9 V = 81000 cubic feet then multiply the volume, 81000, by 7.5, or 607,500 gallons.
hope i helped

6 0

3 years ago

Seventy-two percent of the light aircraft that disappear while in flight in a certain country are subsequently discovered. Of th

Anton [14]

Answer:

a) 0.105 = 10.5% probability that it will not be discovered if it has an emergency locator.

b) 0.522 = 52.2% probability that it will be discovered if it does not have an emergency locator.

c) 0.064 = 6.4% probability that 7 of them are discovered.

Step-by-step explanation:

For itens a and b, we use conditional probability.

For item c, we use the binomial distribution along with the conditional probability.

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

a) If it has an emergency locator, what is the probability that it will not be discovered?

Event A: Has an emergency locator

Event B: Not located.

Probability of having an emergency locator:

66% of 72%(Are discovered).

20% of 100 - 72 = 28%(not discovered). So

$P(A) = 0.66*0.72 + 0.2*0.28 = 0.5312$

Probability of having an emergency locator and not being discovered:

20% of 28%. So

$P(A cap B) = 0.2*0.28 = 0.056$

Probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.056}{0.5312} = 0.105$

0.105 = 10.5% probability that it will not be discovered if it has an emergency locator.

b) If it does not have an emergency locator, what is the probability that it will be discovered?

Probability of not having an emergency locator:

0.5312 of having. So

$P(A) = 1 - 0.5312 = 0.4688$

Probability of not having an emergency locator and being discovered:

34% of 72%. So

$P(A \cap B) = 0.34*0.72 = 0.2448$

Probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.2448}{0.4688} = 0.522$

0.522 = 52.2% probability that it will be discovered if it does not have an emergency locator.

c) If we consider 10 light aircraft that disappeared in flight with an emergency recorder, what is the probability that 7 of them are discovered?

p is the probability of being discovered with the emergency recorder:

0.5312 probability of having the emergency recorder.

Probability of having the emergency recorder and being located:

66% of 72%. So

$P(A \cap B) = 0.66*0.72 = 0.4752$

Probability of being discovered, given that it has the emergency recorder:

$p = P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.4752}{0.5312} = 0.8946$

This question asks for P(X = 7) when $n = 10$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 7) = C_{10,7}.(0.8946)^{7}.(0.1054)^{3} = 0.064$

0.064 = 6.4% probability that 7 of them are discovered.

8 0

3 years ago

HEEEEELLLLPPP ME!!!!!!!!!!!!!!!!!!!!<br> Evaluate u + xy, for u = 2, x = 9, and y = 6.

labwork [276]

Replace u,x and y withyour values
u+xy=2+9*6=2+54=56

5 0

4 years ago

Read 2 more answers

The plans for a shed call for a rectangular floor with a perimeter of 204 ft. The length is two times the width. Find the length

Harlamova29_29 [7]

A-length
b-width
perimeter of rectangular floor: 2a+2b=204
<span>The length is two times the width: a=2b
</span>2a + 2b = 204
2*2b + 2b = 204
6b = 204|:6
b = 34
a=2b=2*34=68

a=68->length
b=34->width

8 0

3 years ago

Read 2 more answers