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Ket [755]
3 years ago
12

Pls help!! ASAP!!!!

Mathematics
1 answer:
Sholpan [36]3 years ago
3 0
Figure A’B’c’d is equal to the measure of angle A
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Is 88,490,144 divisible by 9?
Vlad [161]

Answer:

No

Step-by-step explanation:

The sum of the digits is 40 which is not divisible by 9, so it is not divisible by 9

3 0
3 years ago
Read 2 more answers
Three consecutive odd integers have a sum of 27. Find the integers.
jek_recluse [69]

\sf \bf {\boxed {\mathbb {GIVEN:}}}

Sum of three consecutive odd integers = 27

\sf \bf {\boxed {\mathbb {TO\:FIND:}}}

The values of the three integers.

\sf \bf {\boxed {\mathbb {SOLUTION:}}}

\sf\purple{The\:three\:consecutive \:odd\:integers\:are\:7,\:9\:and\:11.}

\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:\:EXPLANATION:}}}

Let us assume the three consecutive odd integers to be x, (x+2) and (x+4).

As per the condition, we have

Sum \:  \:  of \:  \:  the  \:  \: three \:  \:  consecutive \:  \:  odd \:  \:  integers  = 27

➺ \: x + (x + 2) + (x + 4) = 27

➺ \: x + x + 2 + x + 4 = 27

Now, collect the like terms.

➺ \: (x + x + x) + (2 + 4) = 27

➺ \: 3x + 6 = 27

➺ \: 3x = 27 - 6

➺ \: 3x = 21

➺ \: x =  \frac{21}{3} \\

➺ \: x = 7

Therefore, the three consecutive odd integers whose sum is 27 are \boxed{  7  }, \boxed{ 9   } and \boxed{ 11   } respectively.

\sf \bf {\boxed {\mathbb {TO\:VERIFY :}}}

⇢ 7 + 9 + 11 = 27

⇢ 27 = 27

⇢ L. H. S. = R. H. S.

\sf\blue{Hence\:verified.}

\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35ヅ}}}}}

4 0
3 years ago
If 1 is a solution to g (X)=0 what is the other solution
Lana71 [14]
X can not = 0 because if I did your answer would not be a fraction it would be 0
4 0
3 years ago
What is the d value in the following arithmetic sequence? -7, -2, 3, 8, …
gizmo_the_mogwai [7]

Answer:

+5

Step-by-step explanation:

You add five to -7 you get -2 add five to -2 you get 3 and so on.

4 0
3 years ago
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I need help with number 1 please show work
miv72 [106K]
The last two are the answers
8 0
4 years ago
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