Answer
Hi!, I do not have any idea.
Thanks
Step-by-step explanation:
Answer:
You could use a measurement of 4 centimeters.
The valid range is 2 < x < 8 cms.
Step-by-step explanation:
The third side must either be less than 3+5, that is less than 8 cms and it must be greater than (5-3) = 2 cms. If it is any other length we could not construct a triangle.
Use ratio and proportion
80/120=x/100
cross multiply
x= 66 2/3 percent
Answer:
Domain: (-oo, oo)
Range: (-4,oo)
Horizontal asymptote: y=-4
Answer:
≈ 0.9 cm²
Step-by-step explanation:
I don't know if there is any easier way to solve this, I use 8th grade slope and line method to solve. suppose A is on origin, then the coordinates of triangle ABC are (0,0) (1,3) (4,1) and polygon DEFGH intersect line BC at F and G.
F is the intersect of y=2 and line BC, while G is intersect of x=3 and line BC.
Line BC: pass (1,3) and slope (m) = (1-3)/(4-1) = - 2/3,
F(x,2)
(2-3) / (x-1) = -2/3
2x-2 = 3 x = 2.5
*<u>F (2.5 , 2</u>)
G (3,y)
(y-3) / (3-1) = -2/3 y = 5/3
*<u>G (3 , 5/3)</u>
*<u>point I (3 , 2</u>)
segment FI = 3-2.5 = 0.5 = 1/2
segment GI = 2 - 5/3 = 1/3
area ΔFIG = (1/2 * 1/3) / 2 = 1/12 = 0.083
area of polygon DEFGH (region colored RED) = 1 - 0.083 = 0.917 ≈ 0.9 cm²