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erastova [34]
3 years ago
7

Please help !!!!find a0 when a15=82 and d=3

Mathematics
1 answer:
julsineya [31]3 years ago
4 0
First we don't have a0 the first term is called a1
a15=a1+14d
82=a1+42
a1=40
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Endpoint (-10,9); midpoint (2,5)
Sergeu [11.5K]
<u>x₂ + x₁</u> = m         <u>y₂ + y₁</u> = m<u>
</u>    2                         2
<u>
</u>-10 = x₂
<u />9 = y₂

2=m
5=m

Plug in given numbers

<u>-10 + x</u> = 2                <u>9 + y</u><u /> = 5
      2                              2
Solve

<u>-10 + x</u> = 2*2
     2 *2

-10 + x = 4
+10        +10
         x = 14
(9 + y)/2(2) = 5 (2)
9 + y = 10
-9         -9
      y=1

Final Answer: (14,1)




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3 years ago
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Step-by-step explanation:

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