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2 years ago

7

Please help !!!!find a0 when a15=82 and d=3

1 answer:

julsineya [31]2 years ago

4 0

First we don't have a0 the first term is called a1
a15=a1+14d
82=a1+42
a1=40

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What is the surface area of a conical (cone) grain storage tank that has a height of 24 meters and a diameter of 16 meters?

nirvana33 [79]

Surface area of cone is a sum of surface of its base and surface of its mantle.

Surface of its base is a circle which surface we will calculate like this:
Sb = pi*r^2 where r is d/2
Sb = 201m^2

Surface of mantle we calculate by:
Sm = pi*l*r where l is length of side of cone.

l = $\sqrt{r^2 + H^2}$ = 25.3
Sm = 635.8m^2

Total suface is:
Sb + Sm = 836.8m^2

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2 years ago

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MAXImum [283]

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2 years ago

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2 years ago

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ANTONII [103]

Answer:

Step-by-step explanation:

Recursive formula

tn = t_n-1 / 4

t2 = t1 / 4

t2 = 10240

t1 = 10240 / 4 = 2560

Explicit formula

tn = 10240 / 4^(n-1)

t4 = 10240 / 4^(4 - 1)

t4 = 10240 / 4^3

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6 0

2 years ago

The height of a trapezoid is 6 in. and it’s area is 72 in to the 2nd power. One base of the trapezoid is 6 inches longer than th

Vitek1552 [10]

Given:

The height of the given trapezoid = 6 in

The area of the trapezoid = 72 in²

Also given, one base of the trapezoid is 6 inches longer than the other base

To find the lengths of the bases.

Formula

The area of the trapezoid is

$A=\frac{1}{2} (b_{1} +b_{2} )h$

where, h be the height of the trapezoid

$b_{1}$ be the shorter base

$b_{2}$ be the longer base

As per the given problem,

$b_{2}=b_{1} +6$

Now,

Putting, A=72, $b_{2}=b_{1}+6$ and h=6 we get,

$\frac{1}{2} (b_{1} +b_{1}+6)(6) = 72$

or, $b_{1}+b_{1}+6 = \frac{(72)(2)}{6}$

or, $2b_{1}+6 = 24$

or, $2b_{1}=24-6$

or, $b_{1}= \frac{18}{2}$

or, $b_{1}=9$

So,

The shorter base is 9 in and the other base is = (6+9) = 15 in

Hence,

One base is 9 inches for one of the bases and 15 inches for the other base.

5 0

3 years ago