Question

Find two consecutive odd integers such that their product is 111 more than 3 times their sum​

Answer 1

Answer:

The numbers are -9 and -7 or 13 and 15

Step-by-step explanation:

Let

x and x+2 ----> two consecutive odd integers

we know that

$x(x+2)=3[x+x+2]+111$  

Solve for x

$x(x+2)=3[x+x+2]+111\\ \\x^{2}+2x=6x+6+111\\ \\x^{2}-4x-117=0$

Solve the quadratic equation by graphing

The solution is x=-9, x=13

see the attached figure

First solution

x=-9

x+2=-9+2=-7

The numbers are -9 and -7

Second solution

x=13

x+2=13+2=15

The numbers are 13 and 15