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ale4655 [162]
3 years ago
10

Find two consecutive odd integers such that their product is 111 more than 3 times their sum​

Mathematics
1 answer:
ziro4ka [17]3 years ago
7 0

Answer:

The numbers are -9 and -7 or 13 and 15

Step-by-step explanation:

Let

x and x+2 ----> two consecutive odd integers

we know that

x(x+2)=3[x+x+2]+111  

Solve for x

x(x+2)=3[x+x+2]+111\\ \\x^{2}+2x=6x+6+111\\ \\x^{2}-4x-117=0

Solve the quadratic equation by graphing

The solution is x=-9, x=13

see the attached figure

<em>First solution</em>

x=-9

x+2=-9+2=-7

The numbers are -9 and -7

<em>Second solution</em>

x=13

x+2=13+2=15

The numbers are 13 and 15

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