Find two consecutive odd integers such that their product is 111 more than 3 times their sum
1 answer:
Answer:
The numbers are -9 and -7 or 13 and 15
Step-by-step explanation:
Let
x and x+2 ----> two consecutive odd integers
we know that
Solve for x
Solve the quadratic equation by graphing
The solution is x=-9, x=13
see the attached figure
<em>First solution</em>
x=-9
x+2=-9+2=-7
The numbers are -9 and -7
<em>Second solution</em>
x=13
x+2=13+2=15
The numbers are 13 and 15
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Answer:
Option (D)
Step-by-step explanation:
If the two points and
are lying of the line.
Slope of the line represented by the function 'f' =
Two points are lying on the line are (-2, 4) and (0, -2).
Slope of the line passing through these points 'm' =
m = -3
Y-intercept of the line 'b' = -2 [From the graph]
Therefore, equation of the function will be,
f(x) = (-3)x - 2
f(x) = -3x - 2
Similarly, for other function represented by the line in red,
Slope of the line passing through (-6, 0) and (0, 6) =
m' = 1
Y-intercept of g(x) = 5 [From the graph]
Equation that represents the function g(x) = 1.x + 5
g(x) = x + 5
For g(x) = f(x)
-3x - 2 = x + 6
-3x - x = 2 + 6
-4x = 8
x = -2
Therefore, for x = -2 both the functions will have the value.
f(-2) = g(-2)
Option (D) will be the answer.