Answer:
We conclude that the population mean is different from 10.5.
Step-by-step explanation:
We are given that a random sample of 16 values is drawn from a mound-shaped and symmetric distribution. The sample mean is 11 and the sample standard deviation is 2.
<em>We have to test the claim that the population mean is 10.5.</em>
Let, NULL HYPOTHESIS,
:
= 10.5 {means that the population mean is 10.5}
ALTERNATE HYPOTHESIS,
:
10.5 {means that the population mean is different from 10.5}
The test statistics that will be used here is One-sample t-test;
T.S. =
~ ![t_n_-_1](https://tex.z-dn.net/?f=t_n_-_1)
where,
= sample mean = 11
s = sample standard deviation = 2
= population mean
n = sample of values = 16
So, <u>test statistics</u> =
~ ![t_1_5](https://tex.z-dn.net/?f=t_1_5)
= 1
<em>Now, at 0.05 significance level, t table gives a critical value of 2.131 at 15 degree of freedom. Since our test statistics is way less than the critical value of t so we have insufficient evidence to reject null hypothesis as it will not fall in the rejection region.</em>
Therefore, we conclude that the population mean is different from 10.5.