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3 years ago

I got 7 to go :( help plz

Mathematics

2 answers:

gladu [14]3 years ago

8 0

Answer:

I think the second one is the answer ; 2√b

nikitadnepr [17]3 years ago

6 0

The 2nd one is the answer i’m pretty sure.

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Which angle is formed by a secant and tangent line?

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3 years ago

Luis wants to buy a skateboard that usually sells for $79.91. All merchandise is discounted by %12. What is the total cost of th

quester [9]

Answer:

Luis' skateboard will cost $76.32.

Step-by-step explanation:

Divide 79.91 by 100, this is what one percent is worth, .7991.

Multiply this by 12, giving you 12 percent, 9.59 (rounded to the nearest 10th).

Now subtract 9.59 from 79.91, 70.32. That is the price BEFORE tax.

Than divide 70.32 by 100, .7032.

Multiply this by 8.25, 5.80, this is tax.

Now add the price before tax, 70.32, to the tax, 5.80.

This creates 76.12. This means that the total price of the skateboard is $76.32.

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3 years ago

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“Please help me I will give a BRAINLY and a THANKS and a 5 STAR RATE”

skelet666 [1.2K]

Answer:

i think 55/14 if not srry

Step-by-step explanation:

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3 years ago

The volume of an oblique pyramid with a square base is V units3 and the height is h units.Which expression represents the area o

melamori03 [73]

Answer: a) $\dfrac{3V}{h}\ units^2$

Step-by-step explanation:

We know that the volume of an oblique pyramid is given by :-

$\text{Volume}=\dfrac{1}{3}\text{(Base Area x height) }$

If the volume of an oblique pyramid with a square base is V units³ and the height is h units.

Then, we have

$V=\dfrac{1}{3}\text{(Base Area x h) }$

Multiply 3 on both sides , we get

$3V=\text{(Base Area x h) }$

Divide both sides by h , we get

$\dfrac{3V}{h}=\text{Base Area }$

i.e. $\text{Base Area }=\dfrac{3V}{h}\ units^2$

Hence, the expression represents the area of the base of the pyramid = $\dfrac{3V}{h}\ units^2$

Hence, the correct answer is a) 3 v/h units^2

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3 years ago

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2x^16-32x^4 what is the completely factored form

marysya [2.9K]

Answer:

Step-by-step explanation:

$~~~2x^{16} - 32x^4\\\\ = 2x^4(x^{12} -16)\\\\=2x^4\left[(x^6)^2 - 4^2 \right]\\\\=2x^4(x^6 -4)(x^6 +4)~~~~~~~~~~~~~~~~~~;[a^2 -b^2 = (a+b)(a-b)]\\\\=2x^4\left[(x^3)^2 - 2^2\right] (x^6 +4)\\\\=2x^4(x^3 -2)(x^3 +2)(x^6 +4)$

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2 years ago