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riadik2000 [5.3K]
3 years ago
13

Please answer asap will give the highest points possible

Mathematics
2 answers:
natali 33 [55]3 years ago
6 0
Let cheese wafers = x
chocolate wafers = y

we know they bought 20 total packets so x+y = 20, this can be re-written as x = 20-y

cheese wafers cost 2, so we have 2x
chocolate wafers cost 1, so we have 1y, which is just the letter y

so we know 2x + y = $25

replace x with x=20-y to get:

2(20-y)+y = 25

distribute the parenthesis:

40-2y +y = 25

combine like to terms to get:
40-y = 25

subtract 40 from each side"
-y = -15

divide both sides by -1
y = 15

chocolate wafers was y so they bought 15 chocolate wafers
cheese wafers was x, so they bought 20-15 = 5 cheese wafers
 
using the substitution method was the easiest way to isolate one of the variables in order to find the solution.



Annette [7]3 years ago
4 0

I got the same answer as the guy below me.

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3 times a number xx, subtracted from 1818, is less than -90.?90. Write an inequality for the statement above. Find the solution
Evgen [1.6K]

Answer:

The solution set is: x>36

Step-by-step explanation:

We are given that we have to subtract 3 times of some number 'x' from 18 such that the resulting equation is less than -90.

this means that : 18-3x<-90

on solving the inequality by adding 3x on both side and adding 90 on both side we get that

 108<3x

now on dividing both side by 3 we get that

x>36

Hence our solution set is: x>36


5 0
3 years ago
Read 2 more answers
Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m
GalinKa [24]

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

d=\sqrt{\frac{3h}{2} }

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)

For Addison h=85(1/3)

d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)

Subtracting both distances we get

8\sqrt{2}-6\sqrt{2}  =2\sqrt{2}

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

5 0
2 years ago
The diagram shows 3 ships A, B and C at sea.
Wittaler [7]

Answer:

5km + 4.5km +2.7km = 12.3km

5 0
2 years ago
15
Keith_Richards [23]
Do u have a picture?
5 0
3 years ago
BRAINLIEST! Someone help please!
Papessa [141]

Answer:

60

Step-by-step explanation:

3 0
3 years ago
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