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Anna35 [415]
2 years ago
7

f the centripetal and thus frictional force between the tires and the roadbed of a car moving in a circular path were reduced, w

hat would happen?
Mathematics
1 answer:
LUCKY_DIMON [66]2 years ago
8 0
The frictional force between the tires and the road prevent the car from skidding off the road due to centripetal force.

If the frictional force is less than the centripetal force, the car will skid when it navigates a circular path.

The diagram below shows that when the car travels at tangential velocity, v, on a circular path with radius, r, the centripetal acceleration of v²/ r acts toward the center of the circle.

The resultant centripetal force is (mv²)/r, which should be balanced by the frictional force of μmg, where μ =  coefficient of kinetic friction., and mg is the normal reaction on a car with mass, m.

This principle is applied on racing tracks, where the road is inclined away from the circle to give the car an extra restoring force  to overcome the centripetal force.
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Answer:

c=205

Step-by-step explanation:

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Dennis_Churaev [7]

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32 mins 50 seconds

Step-by-step explanation:

Total number of hours to read weekly \geq 4

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minimum number of minutes to read \geq 32 minutes 50 seconds

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3 years ago
Given the functions, f(x) = x2 + 2 and g(x) = 4x - 1, perform the indicated operation. When applicable, state the domain restric
Naya [18.7K]

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3rd option

Step-by-step explanation:

substitute x = f(x) into g(x)

g(f(x))

= g(x² + 2)

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5 0
2 years ago
Someone plz help!!!!!! ​
aliina [53]

Answer: X = 7√2

Step-by-step explanation:

Let first Consider triangle BDC,

Cos C = adjacent/ hypothenus

Cos C = 7 / x ...... (1)

Also, let consider triangle ABC

Cos C = adjacent / hypothenus

Cos C = x / 14 ....... (2)

Since angle C is the same, equate equation 1 to 2

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Cross multiply

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Make x the subject of formula

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8 0
2 years ago
45% of the population of a city are men
leonid [27]

Answer:

\boxed{\textsf{ The number of children is \textbf{24150}.}}

Step-by-step explanation:

Given that the 45% of the population of a city are men and 15% are children . The number of women is 64,400 . And we need to find the number of children . Here ,

\sf\implies Percentage_{(men)}= 45/% .\\\\\sf\implies Percentage_{(children)}= 15\% .

So the percentage of women will be equal to [ 100 - ( 45 -15) ]% = [ 100 - 60 ]% = 40% .

So let us take the total number of people be x . So ,

\purple{\bigstar}\underline{\underline{\boldsymbol{ According\ to \ Question :- }}}

\sf\implies 40\% \ of \ x \ = \ 64,400 \\\\\sf\implies \dfrac{40x}{100}= 64,400 \\\\\sf\implies x =\dfrac{64,400\times 100}{40}\\\\\sf\implies \boxed{\pink{\sf x = 161,000 }}

\rule{200}2

<u>The </u><u>percentage</u><u> of</u><u> </u><u>children </u><u>=</u><u> </u><u>1</u><u>5</u><u>%</u><u> </u><u>:</u><u>-</u>

\sf\implies Number_{(children)}= 15\% \ of 161,000\\\\\sf\implies Number_{(children)}= \dfrac{15}{100}\times 161,000 \\\\\sf\implies \boxed{\pink{\frak {Number_{(children)}= 24150 }}}

5 0
3 years ago
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