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bearhunter [10]
3 years ago
11

Simplify (x^1/2)^1/6 a. x^1/3 b. x^1/4 c. x^1/12 d. x^2/3

Mathematics
1 answer:
Keith_Richards [23]3 years ago
6 0
(x^{ \frac{1}{2} })^{ \frac{1}{6} }=x^{ \frac{1}{2} * \frac{1}{6} }=x^{ \frac{1}{12} }

Answer is C.
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Find the value of x in the figure<br><br> A: 205°.<br> B: 65°.<br> C: 115°.<br> D: 155°.
Lemur [1.5K]

The answer is [B]: 65°

Connexus??

6 0
3 years ago
Read 2 more answers
I need help! PLEASE HELPP PLEASE HELP!!!
DanielleElmas [232]

Answer:

Part 1: 31x+25=180

part 2: x=5

Step-by-step explanation:

there are 180° on a straight line, which is the base/ bottom line of the traingle (indicated by the arrow on the end).

so, 180-151= 29

29° is the third angle on the traingle.

now, there are 180° in a triangle, therefore to find an equation for x:

29+20x-3+11x-1= 180 (adding up all the angles and making it equal to 180°)

now simplify this equation to get:

31x+25=180 (PART 1)

to find x simply solve the equation:

31x=180-25

31x= 155

x= 155/31

x=5 (PART 2)

4 0
3 years ago
What is the minimum number of bits required to store each binary string of length 50? (b) what is the minimum number of bits req
antiseptic1488 [7]
In order to answer the above question, you should know the general rule to solve these questions.
The general rule states that there are 2ⁿ subsets of a set with n number of elements and we can use the logarithmic function to get the required number of bits.
That is: 
log₂(2ⁿ) = n number of <span>bits
</span>
a). <span>What is the minimum number of bits required to store each binary string of length 50?
</span>
Answer: In this situation, we have n = 50. Therefore,  2⁵⁰ binary strings of length 50 are there and so it would require:

                                                     log₂(2⁵⁰) <span>= 50 bits.

b). </span><span>what is the minimum number of bits required to store each number with 9 base of ten digits?
</span>
Answer: In this situation, we have n = 50. Therefore, 10⁹ numbers with 9 base ten digits are there and so it would require:

                                                     log2(109)= 29.89 
<span>                                                                     = 30 bits. (rounded to the nearest                                                                                                                        whole #)

c).  </span><span>what is the minimum number of bits required to store each length 10 fixed-density binary string with 4 ones?
</span>
Answer: There is (10,4) length 10 fixed density binary strings with 4 ones and
so it would require:
                                                     log₂(10,4)=log₂(210) = 7.7
                                                                    = 8 bits. (rounded to the nearest                                                                                                                        whole #)
4 0
3 years ago
What is 0.351 as a fraction
AlekseyPX

Answer:

351/1000

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Each interior angle of the regular n-gon has a measure of 140
xeze [42]
Sum of internal angles of any polygon is: (n-2)x180
So measure of an interior edge is ( ( n - 2 ) x 180 ) / n = 140
So 140n = 180n - 360
40n = 360
n = 9
So it's a nonagon.

Hope this helps :)
6 0
3 years ago
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