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VladimirAG [237]
3 years ago
15

Can the exponent in the denominator be subtracted from the exponent in the numerator when the based are different? Explain

Mathematics
2 answers:
cricket20 [7]3 years ago
6 0

Answer:no

Step-by-step explanation:

Because u can not subtract a denominator from numerator u must subtract the denominator by the denominator

erastova [34]3 years ago
5 0

Answer:

If the higher power is in the denominator, put the difference in the denominator and vice versa, this will help avoid negative exponents and a repeat of step 3. Step 6: Raise each coefficient (or number) to the appropriate power and then simplify or reduce any remaining fractions. Step 1: Apply the Zero-Exponent Rule.

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Demons answer this for me.
denis-greek [22]

Answer:

Step-by-step explanation:

if you have negative numbers of x (this means negative meters) then the equation transform them into negative yards.

then replace y by 40yd in the equation like

40 = 1.09x

x = 40/1.09 = 36.7 meters

so in a 40yd race, there are 36.7 meters.

4 0
3 years ago
An object is traveling at a speed of 2.5 mph. How long will it take the object to travel 6 miles?
Phoenix [80]

Answer:

It will take him 15 hours to travel 6 miles

Step-by-step explanation:

2.5 miles per hour times 6 miles= 15 hours

8 0
3 years ago
3. What are the roots of the polynomial y = x³ - 8?
zzz [600]

Step-by-step explanation:

x^3 is a perfect cube, 8 is a perfect cube, so we use difference of cubes.

{a}^{3}  -  {b}^{3}  = (a - b)( {a}^{2}  + ab +  {b}^{2} )

Cube root of x^3 is x.

Cube root of 8 is 2

So

a=x

b= 2.

(x - 2)( {x}^{2}  - 2x + 4)

Set these equations equal to zero

x - 2 = 0

x = 2

{x}^{2}  - 2x + 4 = 0

If we do the discriminant, we get a negative answer so we would have two imaginary solutions,

Thus the only real root is 2.

If you want imaginary solutions, apply the quadratic formula.

1 + i  \sqrt{ 3 }

and

1 - i \sqrt{3}

4 0
1 year ago
Please help me with this.
tatyana61 [14]

By understanding and applying the characteristics of <em>piecewise</em> functions, the results are listed below:

  1. r (- 3) = 15
  2. r (- 1) = 11
  3. r (1) = - 7
  4. r (5) = 13

<h3>How to evaluate a piecewise function at given values</h3>

In this question we have a <em>piecewise</em> function formed by three expressions associated with three respective intervals. We need to evaluate the expression at a value of the <em>respective</em> interval:

<h3>r(- 3): </h3>

-3 ∈ (- ∞, -1]

r(- 3) = - 2 · (- 3) + 9

r (- 3) = 15

<h3>r(- 1):</h3>

-1 ∈ (- ∞, -1]

r(- 1) = - 2 · (- 1) + 9

r (- 1) = 11

<h3>r(1):</h3>

1 ∈ (-1, 5)

r(1) = 2 · 1² - 4 · 1 - 5

r (1) = - 7

<h3>r(5):</h3>

5 ∈ [5, + ∞)

r(5) = 4 · 5 - 7

r (5) = 13

By understanding and applying the characteristics of <em>piecewise</em> functions, the results are listed below:

  1. r (- 3) = 15
  2. r (- 1) = 11
  3. r (1) = - 7
  4. r (5) = 13

To learn more on piecewise functions: brainly.com/question/12561612

#SPJ1

7 0
2 years ago
Solve for x.<br><br> x3=125<br><br> Enter your answer in the box.<br><br> x =
olchik [2.2K]

Answer:

x = 5

Step-by-step explanation:

 =(-5-√-75)/2=(-5-5i√ 3 )/2= -2.5000-4.3301i

x =(-5+√-75)/2=(-5+5i√ 3 )/2= -2.5000+4.3301i

x = 5

source tiger-algebra.com

4 0
3 years ago
Read 2 more answers
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