Equation A: 3x + y = 6 Equation B: 6x - 2y = 4 Equation C: y = 3x - 2 Equation D: y = 1 3 x + 7 Which two lines are perpendicula
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2 answers:
Given:
<span>A: 3x + y = 6
</span><span>B: 6x - 2y = 4
</span><span>C: y = 3x - 2
</span><span>D: y = 1/3 x + 7
To figure out which two lines are perpendicular, we must look at the slopes of each one after putting them into standard form, y = mx + b.
Standard Form:
A: y = -3x + 6
B: y = 3x - 2
C: y = 3x - 2
D: y = (1/3)x + 7
Lines are perpendicular when their slopes are opposite inverses of eachother.
The opposite of -3 is 3 and the inverse of 3 is 1/3.
Therefore, lines A and D are perpendicular to one another :)
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Answer: C) A and D
Step-by-step explanation:
Got this right on USA test prep
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