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deff fn [24]
3 years ago
12

Need help with this also plz asap

Mathematics
2 answers:
IRISSAK [1]3 years ago
8 0

Try it randomly idk<em>, sorry I couldn’t help</em>

Bas_tet [7]3 years ago
8 0

For this case, we must expand the series for each value of "n". That is to say:2 ^ {(1) -2} +2 ^ {(2) -2} +2 ^ {(3) -2} +2 ^ {(4) -2} +2 ^ {(5) -2} =

We have that equal signs are added and the same sign is placed, while different signs are subtracted and the sign of the major is placed:

2 ^ {1-2} + 2 ^ {2-2} + 2 ^ {3-2} + 2 ^ {4-2} + 2 ^ {5-2} =

2 ^ {-1} + 2^{0}+ 2^{1} + 2^{2} + 2^{3}=

By definition of power properties we have to:

a ^ {-1} = \frac {1} {a}\\a ^ 0 = 1

So:

\frac {1} {2} + 1 + 2 + 4 + 8 =

We find the common denominator:

\frac {1} {2} + 1 * \frac {2} {2} + 2 * \frac {2} {2} + 4 * \frac {2} {2} + 8 * \frac {2} { 2} =\\\frac {1 + 2 + 4 + 8 + 16} {2} =\\\frac {31} {2} =\\15.5

Answer:

Option B

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