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AlexFokin [52]
4 years ago
7

3y^2-16y+16 could someone help me walk through this?

Mathematics
1 answer:
Lorico [155]4 years ago
8 0
Slip and slide method
3y^2-16y+16
Multiply a by c value and replace as shown below
y^2-16y+48
Factor normally
(y-12)(y-4)
Divide both numbers by the previous a value
(y-12/3)(y-4/3)
(y-4)(y-4/3)
Because -4/3 does not become a whole number change the three to become the coefficient of y
(y-4)(3y-4)
Check by foiling
Final answer: (3y-4)(y-4)
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Answer:

2500

Step-by-step explanation:

let a represent the number of people that had swine flu on the 8th of May

a increased by 37.6% on the 9th of May. The 37.6% increase is equal to 3440

the equation that can be used to represent this is:

a x 1.376 = 3440

to find a, divide both sides by 1.376

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3 years ago
What is the value of x?
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Sabiendo que cada persona unos 4 500 000 glóbulos rojos por milímetro cúbico y que su cantidad de sangre es de 5 litros A) Que l
love history [14]

Answer:

Part A) distance covered by the aligned red cells is: 180000 Km

Part B) 8000000 bacteria (8 million bacteria)

Step-by-step explanation:

Part A)

Let's first find the total number of red cells that the person has in the 5 liters, knowing that there are 4,500,000 of them in a cubic millimetre:

Since 1 liter contains 1,000,000 cubic millimetres, then, in 5 liters there must be 5 times that number of cubic millimetres. That is a total of 5,000,000 cubic millimetres.

Since in each cubic millimetre there are 4,500,000 red cells, then the number of red cells in the 5 liters must be the product of these two quantities:

4,500,000 x 5,000,000 = 22,500,000,000,000 red blood cells.

Now, to find the distance they will cover aligned one after the other, knowing that their average diameter is 0.008 mm is:

22,500,000,000,000 x 0.008 mm= 180000000000 mm

22.5\,\,10^{12} * 8\,\,10^{-3}=1.8\,\,10^{11} mm

In order to convert this distance into Km as requested, we use the fact that 1 mm = 0.000001 Km, or using exponents in base ten:

1 mm = 10^{-6}\,\,Km

Then, the distance covered in kilometers is:

1.8\,\,10^{11}\,*\,10^{-6} \,\,Km=1.8\,\,10^{5}\,\,Km=180000\,\,Km

Part B)

The vaccine contains a total of  10^8  bacteria per cm^3

In order to find how many bacteria we have in 80 mm^3 of the vaccine, we first need to convert 80 mm^3  into cm^3:  

80\,\, mm^3 = 0.08 \,\,cm^3

Then, if in one cm^3 there is 10^8  bacteria, in 0.08\,\,cm^3 there would be: 0.08\,*\,10^8 bacteria. That is: 8\,\,10^6 bacteria = 8000000 bacteria (eight million bacteria)

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3 years ago
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Answer:

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