Answer:
x=17, y=9. (17, 9).
Step-by-step explanation:
x+y=26
3x+8y=123
------------------
x=26-y
3(26-y)+8y=123
78-3y+8y=123
78+5y=123
5y=123-78
5y=45
y=45/5
y=9
x=26-9=17
Answer: The required derivative is 
Step-by-step explanation:
Since we have given that
![y=\ln[x(2x+3)^2]](https://tex.z-dn.net/?f=y%3D%5Cln%5Bx%282x%2B3%29%5E2%5D)
Differentiating log function w.r.t. x, we get that
![\dfrac{dy}{dx}=\dfrac{1}{[x(2x+3)^2]}\times [x'(2x+3)^2+(2x+3)^2'x]\\\\\dfrac{dy}{dx}=\dfrac{1}{[x(2x+3)^2]}\times [(2x+3)^2+2x(2x+3)]\\\\\dfrac{dy}{dx}=\dfrac{4x^2+9+12x+4x^2+6x}{x(2x+3)^2}\\\\\dfrac{dy}{dx}=\dfrac{8x^2+18x+9}{x(2x+3)^2}](https://tex.z-dn.net/?f=%5Cdfrac%7Bdy%7D%7Bdx%7D%3D%5Cdfrac%7B1%7D%7B%5Bx%282x%2B3%29%5E2%5D%7D%5Ctimes%20%5Bx%27%282x%2B3%29%5E2%2B%282x%2B3%29%5E2%27x%5D%5C%5C%5C%5C%5Cdfrac%7Bdy%7D%7Bdx%7D%3D%5Cdfrac%7B1%7D%7B%5Bx%282x%2B3%29%5E2%5D%7D%5Ctimes%20%5B%282x%2B3%29%5E2%2B2x%282x%2B3%29%5D%5C%5C%5C%5C%5Cdfrac%7Bdy%7D%7Bdx%7D%3D%5Cdfrac%7B4x%5E2%2B9%2B12x%2B4x%5E2%2B6x%7D%7Bx%282x%2B3%29%5E2%7D%5C%5C%5C%5C%5Cdfrac%7Bdy%7D%7Bdx%7D%3D%5Cdfrac%7B8x%5E2%2B18x%2B9%7D%7Bx%282x%2B3%29%5E2%7D)
Hence, the required derivative is
Answer:
a. A customer earns 1 free night per 10 nights stayed.
Step-by-step explanation:
The missing function is:
f(x) = x/10
The missing options are:
<em>
a. A customer earns 1 free night per 10 nights stayed. </em>
<em>
b. A customer starts with 1 free night and then earns another free night after every 10 nights stayed.
</em>
<em>
c.A customer earns x – 10 free nights for every 10 nights stayed. </em>
<em>
d. A customer earns 10 free nights after x number of nights stayed.
</em>
The function means that after a customer stayed 10 nights, a free night is earned. That is, replacing x = 10 into the function, we get:
f(10) = 10/10 = 1
which means 10 nights are equivalent to 1 free night.
Jon will be able to run 2 trails because 1/6 time 2 equals 2/6 you can simplify it to 1/3 and 1/3 + 1/3= 2/3
Answer:
Step-by-step explanation:
The first thing that I noticed was that all of the terms had a common factor of 
. You can therefore factor that out first:
Now, you have a quadratic equation inside the parentheses. Factoring, you find that the roots are -0.2 and 3, meaning that you can further factor this expression to be:
Hope this helps!
