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Katena32 [7]
3 years ago
15

What is the value of cos(x) if tan ( x)= -2 and x is in quadrant of IV?

Mathematics
1 answer:
scoray [572]3 years ago
4 0

Answer:

cos(x)=\frac{\sqrt{5}}{5}

Step-by-step explanation:

we have that

tan(x)=-2

The angle x is in quadrant IV

That means ---> The value of cos(x) is positive and the value of sin(x) is negative

Remember that

cos^2(x)+sin^2(x)=1 ----> equation A

tan(x)=\frac{sin(x)}{cos(x)}

so

-2=\frac{sin(x)}{cos(x)}

sin(x)=-2cos(x) ----> equation B

substitute equation B in equation A

cos^2(x)+(-2cos(x))^2=1

solve for cos(x)

cos^2(x)+4cos^2(x)=1

5cos^2(x)=1

cos^2(x)=\frac{1}{5}

square root both sides

cos(x)=\pm\frac{1}{\sqrt{5}}

but remember that the value of cos(x) is positive (IV quadrant)

cos(x)=\frac{1}{\sqrt{5}}

simplify

cos(x)=\frac{\sqrt{5}}{5}

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Triangle PQR has vertices , , and . It is translated according to the rule . What is the y-value of ?
steposvetlana [31]

Answer:

-10 is the correct answer to the given question .

Step-by-step explanation:

Missing information:

Following question is incomplete there is no information about the vertices and the rules .Following are the complete question that is mention below

Triangle PQR has vertices P(-2, 6), \ Q(-8, 4), and\  R(1, -2). It is translated according to the rule    (x, y)\ -> \  (x\  - \ 2, y\  - 16). What is the y-value of P'?

Now coming to the solution as already mention in the question

The translated rule is (x, y)\  -> (x - 2, \ y -16).

Now calculated the vertices P value according to the rule of translated

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Read 2 more answers
Please helpp meeee!!!
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Answer:

im pretty sure the answer would be,

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Step-by-step explanation:

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This 0.0375x shows the number of new recruits which is equivalent to the 65 that is needed by the client if the recruiter.

By equating this 0.0375x to 65,we have:

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