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Alex17521 [72]
3 years ago
12

Question 3 (open to see pic)

Mathematics
1 answer:
melamori03 [73]3 years ago
8 0
The points (1,-2) and (4,16) are not in the line but the point (-3,-18) is on the line. (Work is shown in the image)

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On a piece of paper, graph f(x)=16x0.5^x. Then determine which answer choice matches the graph you drew.
Reil [10]

9514 1404 393

Answer:

  A

Step-by-step explanation:

You can use x=0 and x=1 to find points that must be on the graph.

  f(0) = 16·0.5^0 = 16

  f(1) = 16·0.5^1 = 8

Only graph A matches these points.

7 0
3 years ago
Please solve 108 = 2X-4(2X-9)
Fynjy0 [20]
108=2x-4(2x-9)
108=2x-8x+36
108=-6x+36
-36         -36
72=-6x
72/-6=-6x/-6
-12=x
3 0
2 years ago
what's a math equation that equals 19? it has to be an equation with x and the answer Is 19 so whats the equation guys??
expeople1 [14]
There are many different types of equations we can use to allow x to equal 19! Below are some examples :) See if you can come up with some on your own based off of these examples:

5x = 95.....................................Divide both sides b 5

x = 19.......................................There's one for you :)

_____________________________________________________________

1 + x - 5 = 15............................Combine like terms

x - 4 = 15..................................Add 4 to both sides

x = 19
_____________________________________________________________

There's just a couple of examples, but see if you can come up with some on your own and let me know if you get stuck!

Thank you for your question! I hope this helped! Have an amazing day and feel free to let me know if I can help you any further! :D
3 0
3 years ago
Read 2 more answers
The line y = 7x - 2 has a slope of 7 and a y-intercept of (-2 ,0). TRUE OR FALSE.
8_murik_8 [283]
The y int. is correct but you wrote it wrong it is (0, -2)
5 0
3 years ago
Identify the radius and center.<br><br> x^2 + y^2 - 2x + 4y - 11 = 0
miss Akunina [59]
<h2>Hello!</h2>

The answer is:

Center: (1,-2)

Radius: 4 units.

<h2>Why?</h2>

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

(x-h)^{2}+(y-k)^{2}=r^{2}

Where,

"h" and "k"are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

x^2+y^2-2x+4y-11=0

So, solving we have:

x^2+y^2-2x+4y=11

(x^2-2x+(\frac{2}{2})^{2} )+(y^2+4y+(\frac{4}{2})^{2})=11+(\frac{2}{2})^{2} +(\frac{4}{2})^{2}\\\\(x^2-2x+1)+(y^2+4y+4)=11+1+4\\\\(x^2-1)+(y^2+2)=16

(x^2-1)+(y^2-(-2))=16

Now, we have that:

h=1\\k=-2\\r=\sqrt{16}=4

So,

Center: (1,-2)

Radius: 4 units.

Have a nice day!

Note: I have attached a picture for better understanding.

5 0
3 years ago
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